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ASHA 777 [7]
2 years ago
9

Suppose the charges attracting each other in the above situation have an equal magnitude. Find the charge.

Physics
1 answer:
LiRa [457]2 years ago
7 0

The force between the two point charge when they are separated by 18 cm is 3 N

<h3>How do I determine the force when they are 18 cm apart?</h3>

Coulomb's law states as follow:

F = Kq₁q₂ / r²

Cross multiply

Fr² = Kq₁q₂

Kq₁q₂ => constant

F₁r₁² = F₂r₂²

Where

  • F₁ and F₂ are the initial and new force
  • r₁ and r₂ are the initial and new distance apart

With the above formula, we can obtain the force between the two point charge when they are 18 cm apart. Details below:

  • Initial distance apart (r₁) = 6 cm
  • Initial force of attraction (F₁) = 27 N
  • New distance apart (r₂) = 18 cm
  • New force of attraction (F₂) =?

F₁r₁² = F₂r₂²

27 × 6² = F₂ × 18²

972 = F₂ × 324

Divide both side by 324

F₂ = 927 / 324

F₂ = 3 N

Thus, the force when they are 18 cm apart is 3 N

Learn more about force:

brainly.com/question/28569085

#SPJ1

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