Three point charges are fixed in place in a right triangle, as shown in the figure.

Two parallel wires carry a current in the same direction. there is ___________ between the wires.

Arte-miy333 [17]

The correct answer is "an attractive force" between the wires.

Let's see why. Assume we have wire A on the left and wire B on the right, and that the current in both wires go upward. First, let's find the direction of the magnetic field produced by wire A at wire B: by using the right-hand rule, we see that since the current (the thumb) goes upward, the magnetic field (given by the other fingers) at wire B is directed inside the paper.
Then we can apply again the right-hand rule to see what is the force on wire B. The index gives the direction of the current (upward), the middle finger the direction of the magnetic field (inside the paper), and the thumb gives the direction of the force: to the left, so toward wire A. This means the force is attractive. (you can re-do the procedure on wire A, and you will find the force on wire A is directed toward wire B)

7 0

3 years ago

Which of the following illustrations show atoms of the same element?

egoroff_w [7]

I think it is 1 and 4 hope this helped! ( I am only in middle school)

4 0

3 years ago

A parallel circuit contains four identical lamps. The current through the energy source is 4 A. The total resistance of the circ

TEA [102]

Answer:

b. 40V , 40V

Explanation:

Connections are as per the figure.

As total current through source is 4A , current through each lamp is 1A.

As total resistance of the circuit is 10Ω ,resistance of each bulb is 40Ω because in case of a parallel circuit in which identical objects are connected , $R_{eff} = \frac{R}{n}$ where R is the resistance of each bulb and n is the number of bulbs.

As per Ohm's law , voltage of the source =IR = 4×10 =40V.

We can see from the figure that if the voltage across the source is 40V , the voltage across each bulb is also 40V.

7 0

4 years ago

What is the escape velocity on the Venus ? Venus' mass 4.90*10^ 24 kg and radius is 6.86 * 10 ^ 6 * m

gtnhenbr [62]

The escape velocity on Venus is 9761 m/s

Explanation:

The escape velocity from a planet is the speed that an object on the surface of that planet must have in order to completely escape the gravitational field of the planet.

Mathematically, it is calculated as

$v=\sqrt{\frac{2GM}{R}}$