Answer:

Step-by-step explanation:
In
,
represents a constant related to the period of the function. Here's how it's related:
, where
is the period of the function.
We're given
, so solving for
:

Given:
For cylinder P: radius = 4.25 in. and height = 14 in.
For cylinder Q: radius = 7 in. and height = 8.5 in.
To find:
The volume of each cylinder.
Solution:
Volume of a cylinder is

where, r is radius and h is height. Use 3.14 for
.
Using the above formula, the volume of cylinder P is



Using the above formula, the volume of cylinder Q is


Therefore, the volume of cylinder P is 794.03 sq. in. and volume of cylinder Q is 1307 sq. in.
Answer:

Step-by-step explanation:
Given
The attached plot
Required
The line of the best fit using
and 
We have:


Calculate slope (m)




The equation is then calculated using:


Expand


When considering similar triangles, we need congruent angles and proportional sides.
Hence
"Angles B and B' are congruent, and angles C and C' are congruent." is sufficient to prove similarity of two triangles.
"Segments AC and A'C' are congruent, and segments BC and B'C' are congruent." does not prove anything because we know nothing about the angles.
"Angle C=C', angle B=B', and segments BC and B'C' are congruent." would prove ABC is congruent to A'B'C' if and only if AB is congruent to A'B' (not just proportional).
"<span>Segment BC=B'C', segment AC=A'C', and angles B and B' are congruent</span>" is not sufficient to prove similarity nor congruence because SSA is not generally sufficient.
To conclude, the first option is sufficient to prove similarity (AAA)
Answer:
range is the difference between big and small numbers