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ivanzaharov [21]
1 year ago
13

For part 2 I was told that The circuit below will accommodate up to three resistors in series. Explore the circuit. It is a seri

es circuit with ammeters reading amps hooked in series and volt meters hooked in parallel. The circuit has one resistor and two spaces to accommodate resistors. Enter an R to add resistor. Enter a X to remove a resistor. By default, the cells read "enter R for Resistor" so I did that and tried 3 volts( the pics below) then I was asked Complete each of the following parts:(a) Draw the circuit diagram for the three resistors in series that you assembled in Part 2. Label the voltage and the resistances of each resistor.(b) For the three resistors in series, how did the measured total voltage, current across each resistor, total current, and voltage drop across each resistor compare to the values that you calculated?(c) How did the equivalent resistance, voltage drop across each resistor, total current, and total voltage change as you added resistors in series to the circuit?The resistors value (ohms) is 3Power output volts ( 15,10,5) I put three different ones but if I only need to use one then 15 This is 11th grade physics btw

Physics
1 answer:
Amiraneli [1.4K]1 year ago
5 0

(a) Draw the circuit diagram for the three resistors in series that you assembled in Part 2. Label the voltage and the resistances of each resistor

The diagram will look like the following:

As all the resistors are equal, their voltage drop will also be equal, which will be a third of the input voltage

(b) For the three resistors in series, how did the measured total voltage, current across each resistor, total current, and voltage drop across each resistor compare to the values that you calculated?

The value of the measured voltage on each resistor can be seen as to be exactly as calculated, which is 1/3 of the voltage input. The total current can be calculated as:

I=\frac{V}{R+R+R}=\frac{15}{3*3}=\frac{15}{9}\approx1.7A

Which is the one seen on the amperimeter

(c) How did the equivalent resistance, voltage drop across each resistor, total current, and total voltage change as you added resistors in series to the circuit?

The voltage drop on each resistor will decrease once you add more resistors, as there will be more total resistance, and thus less current. As the resistance of each resistor is constant, the relation V=RI given by Ohm's law will be reduced.

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A competitive go-cart driver is traveling at a speed of 32m/s. He sees a caution flag go up and slows down at a rate of -1.5 m/s
djyliett [7]

Answer:

His final velocity is 15.8 m/s.

Step-by-step explanation:

Given:

Initial velocity of the driver is, u=32 m/s

Acceleration of the driver is, a=-1.5 m/s²

Time taken to reach final velocity is, t=10.8 s.

The final velocity is given using the Newton's equations of motion as:

v=u+at, where, v is the final velocity.

Now, plug in the given values and solve for v.

v=32-1.5(10.8)\\v=32-16.2=15.8\textrm{ m/s}

Therefore, his final velocity is 15.8 m/s.

5 0
3 years ago
A hockey player uses her hockey stick to exert a force of 6.81 N on a stationary hockey puck. The hockey puck has a mass of 165
Anna007 [38]

Answer:

41.3 m/s^2 option (e)

Explanation:

force, F = 6.81 N

mass, m = 165 g = 0.165 kg

Let a be the acceleration of the puck.

Use newtons' second law

Force = mass x acceleration

6.81 = 0.165 x a

a = 41.27 m/s^2

a = 41.3 m/s^2

Thus, the acceleration of the puck is 41.3 m/s^2.

5 0
4 years ago
A projectile is launched from the ground at an angle of 60o above the horizontal. At what point in its trajectory does it have t
Elodia [21]

Answer:

It's constant everywhere in its trajectory.

Explanation:

the projectile was launched with an initial velocity, the only acceleration that is affecting the projectile's velocity is gravity.

The acceleration of gravity is practically equal everywhere on earth, so during its trajectory, we have to take into consideration only the acceleration because of gravity.

This is only correct because the projectile was launched with an initial velocity and it's not accelerating from rest and then falls.

5 0
3 years ago
Fill in the blanks for the following:
storchak [24]

Answer:

<em>a. 4.21 moles</em>

<em>b. 478.6 m/s</em>

<em>c. 1.5 times the root mean square velocity of the nitrogen gas outside the tank</em>

Explanation:

Volume of container = 100.0 L

Temperature = 293 K

pressure = 1 atm = 1.01325 bar

number of moles n = ?

using the gas equation PV = nRT

n = PV/RT

R = 0.08206 L-atm-mol^{-1}K^{-1}

Therefore,

n = (1.01325 x 100)/(0.08206 x 293)

n = 101.325/24.04 = <em>4.21 moles</em>

The equation for root mean square velocity is

Vrms = \sqrt{\frac{3RT}{M} }

R = 8.314 J/mol-K

where M is the molar mass of oxygen gas = 31.9 g/mol = 0.0319 kg/mol

Vrms = \sqrt{\frac{3*8.314*293}{0.0319} }= <em>478.6 m/s</em>

<em>For Nitrogen in thermal equilibrium with the oxygen, the root mean square velocity of the nitrogen will be proportional to the root mean square velocity of the oxygen by the relationship</em>

\frac{Voxy}{Vnit} = \sqrt{\frac{Mnit}{Moxy} }

where

Voxy = root mean square velocity of oxygen = 478.6 m/s

Vnit = root mean square velocity of nitrogen = ?

Moxy = Molar mass of oxygen = 31.9 g/mol

Mnit = Molar mass of nitrogen = 14.00 g/mol

\frac{478.6}{Vnit} = \sqrt{\frac{14.0}{31.9} }

\frac{478.6}{Vnit} = 0.66

Vnit = 0.66 x 478.6 = <em>315.876 m/s</em>

<em>the root mean square velocity of the oxygen gas is </em>

<em>478.6/315.876 = 1.5 times the root mean square velocity of the nitrogen gas outside the tank</em>

6 0
3 years ago
When two or more capacitors are connected in series across a potential difference:
34kurt

Answer:

A) and B) are correct.

Explanation:

Let's take a look at the attached picture. Now

The total voltage across both capacitors is the same as the sum of the voltage from each device, that statement is true for any electrical device connected in series. So a) is TRUE

The equivalent capacitance is going to be: \frac{1}{C_{total}}=\frac{1}{C_1} +\frac{1}{C_2}

And that value can be mathematically proven that is always less than any of the values of each capacitor. So b is TRUE

And through both capacitors flow the same current, but the amount of charge depends on the value of the capacitors, so only could be the same if the capacitors are the same value. Otherwise, don't. C) not always, so FALSE

7 0
3 years ago
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