Answer:HERE IS YOUR ANSWER
THE POINTS ARE
IF WE PUT THE OBJECT BETWEEN THE FOCUS
AND THE POLE
THEN THE IMAGE FORMED WILL be MAGNIFIED
If that’s not what you are looking for, try this one:
For concave mirror the virtual image is formed when the object is kept in between the pole and the focus.
Given here the "size of the image" is twice to that of the object.
Hence, it is consider that the magnification is +2.
So, the magnification value is positive and the image formed will be "virtual and erect". Thus, the object should be kept in between the "pole and the focus" in concave mirror."
Explanation:
Answer:
Suppose any object with mass in our planet.
The object will be affected by the gravitational force, that pulls the object down. Now, a table in your dining room is also affected by this force, but the table is in a surface (the ground) and it does not move.
We know that if an object does not move, then the net force acting on it is equal to zero, this means that there is a force equal and opposite ot the gravitational force.
This force is the normal force, that the ground applies on the table. This force comes as a "response" to the table pushing the ground (By 3rd Newton's law).
So two forces that are always equal and opposite are the forces caused by this law.
Answer:
983.400345675 hits per second
Explanation:
Radius = 14.2 cm
Record turn rate = 33 rev/min
Bump separation = 0.499 mm
Circumference of the record = 
Number of bumps in the groove = 
The rate which the bumps hit the stylus = 
The rate at which the bumps hit the stylus 983.400345675 hits per second
Answer:
minimum length of runway is needed for take off 243.16 m
Explanation:
Given the data in the question;
mass of glider = 700 kg
Resisting force = 3700 N one one glider
Total resisting force on both glider = 2 × 3700 N = 7400 N
maximum allowed tension = 12000 N
from the image below, as we consider both gliders as a system
Equation force in x-direction
2ma = T -f
a = T-f / 2m
we substitute
a = (12000 - 7400 ) / (2 × 700 )
a = 4600/1400
a = 3.29 m/s²
Now, let Vf be the final speed and Ui = 0 ( as starts from rest )
Vf² = Ui² + 2as
solve for s
Vf² = 0 + 2as
2as = Vf²
s = Vf² / 2a
given that take of speed for the gliders and the plane is 40 m/s
we substitute
s = (40)² / 2×3.29
s = 1600 / 6.58
s = 243.16 m
Therefore, minimum length of runway is needed for take off 243.16 m
Answer:
The order of steps for writing a chemical formula is 3, 2, 1, 5, 4
Explanation:
Balance the charges. Identify the negative ion and charge. Identify the positive ion and charge. Use the information in the ratio to write the chemical formula. Write the ratio of ions that balances the charges.
The order of steps for writing a chemical formula from the options above is:
3.) Identify the positive in and charge.
2.) Identify the negative ion and charge.
1.) Balance the charges.
5.)Write the ratio of ions that balances the charges.
4.) Use the information in the ratio to write the chemical formula.
