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3 years ago

Helpppppp :((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((9999

Mathematics

1 answer:

Anni [7]3 years ago

4 0

Answer is C and E.

All of the other ones don't follow order of operations properly.

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There are 2000 pounds in a ton how can you write 2000 with and exponent

Makovka662 [10]

In scientific notation, it would be 2x10^3.
An easy trick to help remember when it is a multiple of 10 is that you do the numbers that aren't zero (2) times 10 and the exponent is how ever many zeros there are after the other numbers (3).

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3 years ago

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Y= -8/9 (x+1)+6 <br> convert to standard form

Trava [24]

Answer:

kl l

Step-by-step explanation:

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2 years ago

Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.

Ann [662]

Note that if ${x_2}'=x_1$ , then ${x_2}''={x_1}'$ , and so we can collapse the system of ODEs into a linear ODE:

${x_2}''=3{x_2}'-x_2+e^t$
${x_2}''-3{x_2}'+x_2=e^t$

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

$r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0$

so that the characteristic solution is

${x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}$

Now let's suppose the particular solution is ${x_2}_p=ae^t$ . Then

${x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t$

and so

$ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1$

Thus the general solution for $x_2$ is

$x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t$

and you can find the solution $x_1$ by simply differentiating $x_2$ .

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3 years ago

Does anyone know what 3.2 ÷ 0 ???

Assoli18 [71]

Answer:

Infinity

Step-by-step explanation:

Look it up, its how it works. 0 can go into 3.2 infinity times.

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3 years ago

Please help! the ppl who are good atttt mathhh please!

Nata [24]

Answer:

10) SAS

12) SAS

13) SSS

11) ASA

14) ASA

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3 years ago

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