Hello
f(x) = 2sin(x)
f(<span>π/6) = 1
f'(x) 2cos(x)
f'(</span>π/6) = 2×co(π/6) = 2 × root(3)×0.5 =root(3)
The equation of this tangent line is : y= root(3)(x-π/6)+1
y = root(3)x+1 - π/6(root(x)) <span>in the form y=mx+b
m = root(3) and b = </span>1 - π/6(root(x))
Answer: (4,4)
Step-by-step explanation:
(1,-4) reflected over the x-axis is (1,4). Then translated 3 units up is (4,4). Hope this helps
Step-by-step explanation:
The period of f(x) is π.
To calculate the period using the formula derived from the basic sine and cosine equations. The period for function y = A sin (B a – c) and y = A cos ( B a – c ) is equal to 2πB radians. The reciprocal of the period of a function is equal to its frequency.
Answer: the answer is b
Step-by-step explanation:
Answer:
Y= 5x + 17
Step-by-step explanation:
Y-y1= m(x-x1)
Y- -3= 5(x- -4)
Y+ 3= 5x +20
Y= 5x + 17