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zubka84 [21]
3 years ago
7

Solution to 3x+5y=-20

Mathematics
2 answers:
Wewaii [24]3 years ago
7 0
Answer: 20


3x+5y=-20

5y=-20divide

answer is x=-4

3x=-20 divide

the answer is y=-20



I hope this helps and have a wonderful day filled with joy!!

zloy xaker [14]3 years ago
3 0

3x+5y=-20

5y=-20divide

the answer is x=-4

3x=-20 divide

the answer is y=-20

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150

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Round 46 to the nearest ten, which in this case would be 50 because the last number is larger than a 5. 

Then add the 1 back in to make it 150.
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20% of US High School teens vape. A local High School has implemented campaigns to reduce vaping among students and believes tha
zaharov [31]

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10.93% probability of observing 51 or fewer vapers in a random sample of 300

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

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Can be approximated to a normal distribution, using the expected value and the standard deviation.

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The standard deviation of the binomial distribution is:

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Normal probability distribution

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In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 300, p = 0.2

So

\mu = E(X) = np = 300*0.2 = 60

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{300*0.2*0.8} = 6.9282

What is the approximate probability of observing 51 or fewer vapers in a random sample of 300?

Using continuity corrections, this is P(X \leq 51 + 0.5) = P(X \leq 51.5), which is the pvalue of Z when X = 51.5 So

Z = \frac{X - \mu}{\sigma}

Z = \frac{51.5 - 60}{6.9282}

Z = -1.23

Z = -1.23 has a pvalue of 0.1093.

10.93% probability of observing 51 or fewer vapers in a random sample of 300

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