Aditi bought 20 apples at Rs 25 each and sold them at Rs 32 each. What is her total profit?

PLEASE HELPPPP A Kite is a Parallelogram. Always Never Sometimes

ipn [44]

Answer:

Never

Step-by-step explanation:

This statement is false because a kite is a quadrilateral that has two adjacent equal sides (upper side and lower side). In a parallelogram, two opposite sides are equal in measure.

3 0

3 years ago

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Plz help number 4 plz rn

ruslelena [56]

The answer for this qeustion is C.

7 0

3 years ago

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Which values of x would make a polynomial equal to zero if the factors of the polynomial were (x-5) and (x-6)

meriva

x-5= 0

move -5 to the other side

sign changes from -5 to +5

x-5+5= 0+5

x= 5

x-6= 0

x-6+6= 0+6

x= 6

Answer: B. 5 and 6

5 0

3 years ago

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Graph the line y+3=-1/4(x-3)

insens350 [35]

Answer:

Make a table with values of x and y using the equation y + 3 = -1/4(x - 3) :

x y

0 -2.25

3 -3

5 -3.5

-1 -2

-9 0

Now, graph these and draw a line through the points:

4 0

3 years ago

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Of the entering class at a college, % attended public high school, % attended private high school, and % were home schoole

Veronika [31]

Answer:

(a) The probability that the student made the Dean's list is 0.1655.

(b) The probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c) The probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

Step-by-step explanation:

The complete question is:

Of the entering class at a college, 71% attended public high school, 21% attended private high school, and 8% were home schooled. Of those who attended public high school, 16% made the Dean's list, 19% of those who attended private high school made the Dean's list, and 15% of those who were home schooled made the Dean's list.

a) Find the probability that the student made the Dean's list.

b) Find the probability that the student came from a private high school, given that the student made the Dean's list.

c) Find the probability that the student was not home schooled, given that the student did not make the Dean's list.

Solution:

Denote the events as follows:

A = a student attended public high school

B = a student attended private high school

C = a student was home schooled

D = a student made the Dean's list

The provided information is as follows:

P (A) = 0.71

P (B) = 0.21

P (C) = 0.08

P (D|A) = 0.16

P (D|B) = 0.19

P (D|C) = 0.15

(a)

The law of total probability states that:

$P(X)=\sum\limits_{i} P(X|Y_{i})\cdot P(Y_{i})$

Compute the probability that the student made the Dean's list as follows:

$P(D)=P(D|A)P(A)+P(D|B)P(B)+P(D|C)P(C)$

$=(0.16\times 0.71)+(0.19\times 0.21)+(0.15\times 0.08)\\=0.1136+0.0399+0.012\\=0.1655$

Thus, the probability that the student made the Dean's list is 0.1655.

(b)

Compute the probability that the student came from a private high school, given that the student made the Dean's list as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D)}$

$=\frac{0.21\times 0.19}{0.1655}\\\\=0.2410876\\\\\approx 0.2411$

Thus, the probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c)

Compute the probability that the student was not home schooled, given that the student did not make the Dean's list as follows:

$P(C^{c}|D^{c})=1-P(C|D^{c})$

$=1-\frac{P(D^{c}|C)P(C)}{P(D^{c})}\\\\=1-\frac{(1-P(D|C))\times P(C)}{1-P(D)}\\\\=1-\frac{(1-0.15)\times 0.08}{(1-0.1655)}\\\\=1-0.0815\\\\=0.9185$

Thus, the probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

3 0

3 years ago

Aditi bought 20 apples at Rs 25 each and sold them at Rs 32 each. What is her total profit?​

Aditi bought 20 apples at Rs 25 each and sold them at Rs 32 each. What is her total profit?