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Nostrana [21]
3 years ago
8

Which of the following is an undefined term? a. angle b. line c. ray d. vertex

Mathematics
2 answers:
love history [14]3 years ago
5 0
The three undefined terms in geometry are line, point, and plane. So:
Your answer is B

I hope this helps:)
WITCHER [35]3 years ago
3 0

Answer: b. line

Step-by-step explanation:

We know that in geometry, there are three undefined terms and they are

1) point (no dimension)

2) line (one dimension)

3) plane (two dimension)

Therefore, from the given options the undefined term is 'line'.

In geometry a line is defined as a shape that is extending infinitely in two directions but has no width. It is one dimensional .

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Simplify each expression using the proper order of operations. please help thank you so much :)
Tasya [4]

Answer:

\frac{41 - 3^2}{\sqrt{36} * 3 - 26} = -4

12 + 3\sqrt{8} * (9 - 2) = 12 + 42 \sqrt{2}

\frac{28 - (7^2 + 3)}{-13 + 3 * 5} = -12

7^2 - 5* 8+1 = 10

(2 * \sqrt{16}) - (\sqrt[3]{27} * \sqrt{81}) + 1 = -18

Step-by-step explanation:

<em>Required: Solve the expressions using proper operation order</em>

To solve this, we'll make use of BODMAS

--------------------------------------------------------------------------------------------------------

\frac{41 - 3^2}{\sqrt{36} * 3 - 26}

Evaluate all squares and square roots

\frac{41 - 3*3}{\sqrt{36} * 3 - 26}

\frac{41 - 3*3}{6 * 3 - 26}

Evaluate the numerator (Start by multiplying 3 * 3)

\frac{41 - 9}{6 * 3 - 26}

Subtract 9 from 41

\frac{32}{6 * 3 - 26}

Evaluate the denominator (Start by multiplying 6 * 3)

\frac{32}{18 - 26}

\frac{32}{-8}

Divide 32 by -8

-4

Hence;

\frac{41 - 3^2}{\sqrt{36} * 3 - 26} = -4

--------------------------------------------------------------------------------------------------------

12 + 3\sqrt{8} * (9 - 2)

Start by evaluating the bracket

12 + 3\sqrt{8} * 7

Then evaluate the multiplication

12 + 21\sqrt{8}

Simplify the square root

12 + 21\sqrt{4 * 2}

Split the square root

12 + 21\sqrt{4} * \sqrt{2}

Take Square root of 4

12 + 21 * 2} * \sqrt{2}

12 + 42 \sqrt{2}

Hence;

12 + 3\sqrt{8} * (9 - 2) = 12 + 42 \sqrt{2}

--------------------------------------------------------------------------------------------------------

\frac{28 - (7^2 + 3)}{-13 + 3 * 5}

Evaluate 7²

\frac{28 - (49 + 3)}{-13 + 3 * 5}

Evaluate all expression in the bracket

\frac{28 - (52)}{-13 + 3 * 5}

\frac{28 - 52}{-13 + 3 * 5}

Evaluate 3 * 5

\frac{28 - 52}{-13 + 1 5}

\frac{-2 4}{2}

-12

Hence;

\frac{28 - (7^2 + 3)}{-13 + 3 * 5} = -12

--------------------------------------------------------------------------------------------------------

7^2 - 5* 8+1

Evaluate 7²

49 - 5* 8+1

Evaluate 5 * 8

49 - 40 + 1

10

7^2 - 5* 8+1 = 10

--------------------------------------------------------------------------------------------------------

(2 * \sqrt{16}) - (\sqrt[3]{27} * \sqrt{81}) + 1

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(2 * 4) - (3 * 9) + 1

Solve the expressions in bracket

8 - 27 + 1

-18

Hence;

(2 * \sqrt{16}) - (\sqrt[3]{27} * \sqrt{81}) + 1 = -18

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