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Zina [86]
1 year ago
13

Use a table of values with at least 5 values to graph the following function:

Mathematics
1 answer:
34kurt1 year ago
4 0

The given expression :

y=(\frac{1}{2})^x

For coordinates:

put x = 0 then :

\begin{gathered} y=(\frac{1}{2})^0 \\ y=1 \end{gathered}

Coordinate : (x, y) = (0, 1)

Put x= 1 and simplify :

\begin{gathered} y=(\frac{1}{2})^1 \\ y=\frac{1}{2} \\ y=0.5 \end{gathered}

Coordinate : (x, y) = ( 1, 0.5)

Put x = (-2) and simplify :

\begin{gathered} y=(\frac{1}{2})^{-2} \\ y=\frac{1^{-2}}{2^{-2}} \\ y=\frac{2^2}{1^2} \\ y=2^2 \\ y=4 \end{gathered}

Coordinate : (x, y) = ( -2, 4)

Put x = (-3) and simplify :

\begin{gathered} y=(\frac{1}{2})^{-3} \\ y=\frac{1^{-3}}{2^{-3}} \\ y=\frac{2^3}{1^3} \\ y=2^3 \\ y=8 \end{gathered}

Coordinate : (x, y) = (-3, 8)

Substitute x = (-1) and simplify :

\begin{gathered} y=(\frac{1}{2})^x \\ y=(\frac{1}{2})^{-1} \\ y=\frac{1^{-1}}{2^{-1}} \\ y=\frac{2}{1} \\ y=2 \end{gathered}

Coordinate : (x, y) = ( -1, 2)

So, the coordinates are :

The graph is :

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Find the common fraction equivalent to 0.12
jonny [76]
The answer is:  " \frac{4}{33} "  .
______________________________
Given:  0.1212121212..... repeating ;  write that value as a fraction;
______________________________________________________
In other words; we are given:  "0.1212121212..... repeating infinitely" ;  

→ that is to say; "0.12 ...  ;  {the "12" decimal portion repeats infinitely} ; 
_______________________________________________________
→ We write this value, as a fraction, as:  "12/99" ;
__________________________________________
→Explanation:
__________________________________________ 


Note:  "0.99999999...... repeating infinitely;  =  "1" .
_________________________________________
→Since:

Let us say that we have: 

"x = 0.999999 ; repeating infinitely;  

In order words, let us say we have: "x = 0.9.... ;  the "9" decimal repeats infinitely; 
_____________________________________________________
   Then "10x" ;  (that is: "10" multlipled by "x";  or "10*x" or "10x" );  is equal to:

"10" * (0.999999.....)  = 9.99999999...... (the "9" decimal repeats infinitely);

in other words:  10x = 9.99999999....

Divide each side by "10" ;

to get "x = 0.9999999....." ; the decimal "9" repeats indefinitely...." ;

But if you have:  "10x = 10" ;  divide each side of the equation by "10" ; 
   you get: "x = 1" . 
____________________
Also,  if "x = 0.9999...(repeating infinitely); 

then:  10x = 9.99999.
_______________________________________________
           10x  =  9.999999999999999......
       −     x  =  0.999999999999999.......
    _____________________________________
            9x  =  9.00000000000000000000.....

 →  9x = 9 ; 

Divide each side of the equation; to get; 

 9x /9 = 9/ 9 ;  to get:  x = 1 ; and we have: x = 0.9999.... ;  so
  x= 0.99999.... = 1 ; 
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So, if the numbers "12" is repeating, we divie "12" by "99" ; 
  that is; we divide "12" by "two 9's" ;  since "12" is a "TWO-digit number"; a "two-digit number" is being repeated infinitely.
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            So;  0.12121212.....(the "12" is the decimal that repeats infinitely);            
                   
=  12/99 ;  which can be simplified;

Divide each side (both the numerator AND the denominator); by "3" ;
_________________________________________
  " 12/99 "  =  "(12÷3) / (99÷3) = 4/33 " .
_________________________________________
The answer is:  \frac{4}{33}  .
_________________________________________
8 0
3 years ago
Read 2 more answers
answers please asap for this question please i have been waiting for ever and its due tomorrow the 10th
ololo11 [35]
Hi there!

First, let's create an equation for the table: m = 2n + 40. Using this equation, we can find the values of x, y, and z.

WORK:
x = 2(4) + 40
x = 8 + 40
x = 48
y = 2(5) + 40
y = 10 + 40
y = 50
z = 2(6) + 40
z = 12 + 40
z = 52

Next, using the equation, we know that the initial investment would be 40, since that is the y-intercept of the equation. To express M in terms of N, that would be our equation m = 2n + 40. To find 10 years, we'll plug in 10 for n.

WORK:
m = 2(10) + 40
m = 20 + 40
m = 60 after 10 years

To figure out when his investment would double, we'll need to use 80 (double his initial investment of 40) in place of m.

WORK:
80 = 2n + 40
40 = 2n
n = 20 years


Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
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3 years ago
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11111nata11111 [884]

function composition is an operation that takes two functions f and g and produces a function h such that h(x) = g(f(x)). In this operation, the function g is applied to the result of applying the function f to x.

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What percent of 20 is 40?<br> A 50%<br> B 75%<br> C 100%<br> D 200%
svet-max [94.6K]

It was

40 is 200% of 20

7 0
3 years ago
5646534 + 746386785634986789376589674987654<br> REPOST LOL
Tresset [83]

Answer:

7.4638679e+32

Step-by-step explanation:

5646534 + 746386785634986789376589674987654

=7.4638679e+32

8 0
2 years ago
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