Total distance travelled by the car is 'd'
<span>distance trveled before the brakes were applied = v_o * t </span>
<span>distance travld with brakes = d - v_o*t </span>
<span>applying the formula: v^2 - u^2 = -2 a * s </span>
<span>=> 0 - v_o^2 = -2 * a_x * (d- v_o*t) </span>
<span>=> a_x = (v_o^2)/ ( 2 (d-v_o*t)</span>
Answer:
(A) Original velocity will be 7.244 m /sec
(B) Acceleration will be 
Explanation:
We have given distance covers by truck s = 40 m
Time taken by truck to cover this distance t = 7.45 sec
Final velocity v = 3.50 sec
According to second equation of motion


-----eqn 1
According to first equation of motion
v = u + at
So
-----eqn2
Solving equation 1 and 2
a = 
And u = 7.244 m /sec
(A) Original velocity will be 7.244 m /sec
(B) Acceleration will be

Answer:A).3.16 s B).56.92
A).12.5m/s
B).7.81m
Explanation:
Complete Question
The complete question is shown on the first uploaded image
Answer:
The value is 
Explanation:
From the question we are told that
The mass of the wheel is m = 6.9 kg
The radius is 
The radius of gyration is 
The angle is 
The force which the massless bar is subjected to 
Generally given that the wheels rolls without slipping on the flat stationary ground surface, it implies that point A is the center of rotation.
Generally the moment of inertia about A is mathematically represented as

Here
is the moment of inertia about G with respect to the radius of gyration which is mathematically represented as

=>
=>
=>
Generally the torque experienced by the wheel is mathematically represented as

=> 
=> 
Generally this torque is also mathematically represented as

=> 
=> 
Answer: If the other two frequencies are F and F1 then;
F-364=2
F=364+2
F=366Hz
364-F1=2
F1=364-2
F1=362Hz
Hence the two possible frequencies are 362Hz and 366Hz
Explanation: