To calculate the horizontal distance traveled by the shot if it leaves the athlete's hand at a height of 2.20 above the ground we can get the root of the quad equation for time are t=-0.24 or t =1.84 taking the t = 1.84, so the equation will be:
x = 15.6cos(30) * 1.86, x = 24.79m
<span>potential energy because it has the ability to do work
*A*</span>
Answer:
The correct choice is 8o.
Explanation:
The given weight is hanging at the mid point of the rope and the buildings are at the same level, Obtain the given equation by equating the vertical components of force,
2Tsin(φ)=W
where φ is the angle made by rope with the horizontal.
Given T=1800 N and W=500 N, the value of φ is calculated as follows,
2*1800*sin(φ)=500
sin(φ)=0.1388
φ=7.90
φ≈8o
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