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Klio2033 [76]
3 years ago
9

How do you know the earth is rotating on its axis

Physics
1 answer:
cupoosta [38]3 years ago
4 0

Answer:

Read below!

Explanation:

You can watch the sun wheel across the sky during the day, and the stars at night. Focus a telescope on any star besides the north star--especially southern stars--and you can watch them drift across your field of view.  

An alternative explanation is that all the stars are painted on (or holes in) some canopy that rotates around the earth. This explanation does not account for the motion of the "wanderers," or planets, as the Greeks called them, or for the path of the moon among the stars.  

As we know the stars are massive bodies of significant and varying distance to the earth, the notion they all swing around us in unison seems highly implausible

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Volgvan
1. C
2. A
3. E
4. D
5. B
6. F
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4 0
3 years ago
Read 2 more answers
At the beach in San Francisco (0 meters) the pressure of the atmosphere is 101.325 kPa
Korvikt [17]

Answer:

P = -\frac{17978}{1609344}(h)+101.325

Explanation:

Given

h = height

P = Pressure

(h_1,P_1) = (0,101.325)

(h_2,P_2) = (1609.344 ,83.437 )

Required

Determine the linear equation for P in terms of h

First, we calculate the slope/rate (m);

The following formula is used:

m = \frac{P_2 - P_1}{h_2 - h_1}

Substitute values for P's and h's

m = \frac{83.347 - 101.325}{1609.344- 0}

m = \frac{-17.978}{1609.344}

m = -\frac{17.978}{1609.344}

Multiply by 1000/1000

m = -\frac{17.978 * 1000}{1609.344*1000}

m = -\frac{17978}{1609344}

The equation is then calculated using:

P - P_1 = m(h - h_1)

Substitute values for m, h1 and P1

P - P_1 = m(h - h_1)

P - 101.325 = -\frac{17978}{1609344}(h - 0)

P - 101.325 = -\frac{17978}{1609344}(h)

Make P the subject

P = -\frac{17978}{1609344}(h)+101.325

<em>The above is the required linear equation</em>

8 0
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kaheart [24]

Answer:

Sometimes may cause involuntary responses like twitching

Explanation:

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Answer:

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Explanation:

:) hope this helps. Have a great day!

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What two factors determine gravitational potential energy?
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