Compression is to crest as rarefaction is to ________

Naily [24]

Answer:

50m/s, 187.5m

Explanation:

Consider unit analysis:

m/s² = m/(s×s)

This can be read as "meters per second, per second". From fundamental kinematics, meters per second is the same as saying velocity.

Velocity is being increased per second, and this is called acceleration:

a = v/t, where a is acceleration, v is change of velocity and t is change of time. "Change" is represented by a triangle called delta and (delta)A = A2 - A1

From the question, we have the variables:

a = 5m/s²

(delta)v = v2 - 25m/s

(delta)t = 5s (initial time is 0)

a = v/t

(5m/s^2)=v/5s

25m/s = v2 - 25m/s

50m/s = v2

The final velocity of the vehicle is 50m/s.

A formula exists to find displacement with regards to acceleration:

d=v(initial) × t +1/2 × a × t²

d=25m/s × 5s + 1/2 × 5m/s² ×(5s)²

d=125m+1/2×125m

d=125m+62.5m

d=187.5m

The distance travelled by the vehicle is 192.5m.

One of the most important skills you can have in any science is unit analysis. Treat meters, seconds, moles, etc as values when doing calculations and see if you get the result you're looking for.

7 0

3 years ago

Suppose the coefficient of static friction between a quarter and the back wall of a rocket car is 0.383. At what minimum rate wo

djverab [1.8K]

Answer:

25.59 m/s²

Explanation:

Using the formula for the force of static friction:

$f_s = \mu_s N$ --- (1)

where;

$f_s =$ static friction force

$\mu_s =$ coefficient of static friction

N = normal force

Also, recall that:

F = mass × acceleration

Similarly, N = mg

here, due to min. acceleration of the car;

$N = ma_{min}$

From equation (1)

$f_s = \mu_s ma_{min}$

However, there is a need to balance the frictional force by using the force due to the car's acceleration between the quarter and the wall of the rocket.

Thus,

$F = f_s$

$mg = \mu_s ma_{min}$

$a_{min} = \dfrac{mg }{ \mu_s m}$

$a_{min} = \dfrac{g }{ \mu_s }$

where;

$\mu_s = 0.383$ and g = 9.8 m/s²

$a_{min} = \dfrac{9.8 \ m/s^2 }{0.383 }$

$\mathbf{a_{min}= 25.59 \ m/s^2}$

3 0

3 years ago

A tsunami, an ocean wave generated by an earthquake, propagates along the open ocean at 700 km/hr and has a wavelength of 750 km

Colt1911 [192]

Answer:

C) 0.00026 Hz

Explanation:

In any wave, there exists a fixed relationship between the speed v, the frequency f and the wavelength λ, as follows:

$v = \lambda * f (1)$

Replacing by the givens in (1), and solving for f, we get:

$f = \frac{v}{\lambda} = \frac{700km/hr}{750 km} = 0.93 1/hr (2)$

Converting the units to Hz (1/sec), we get:

$f = 0.93 \frac{1}{hr} *\frac{1 hr}{3600sec} = 2.6e-4 = 0.00026 Hz (2)$

The answer C. is the right one.

7 0

3 years ago

two vehicles have a head on collision. one vehicle has a mass of 3000 kg and moves at 25 m/s while the second vehicle has a mass

emmasim [6.3K]

Answer:

The speed of the combined vehicles is 6.82m/s

Explanation:

Using the law of conservation of momentum which stayed that the sum of momentum of bodies before collision is equal to their sum of momentum after collision. After collision, both object moves with the same velocity.

Momentum = mass×velocity

Before collision:

Momentum of vehicle or mass 3000kg moving with velocity 25m/s

= 3000×25

= 75000kgm/s

Pa = 75000kgm/s

Momentum of vehicle with mass 2500kg moving with velocity of -15m/s

= 2500×-15

= -37500kgm/s

After collision:

Momentum = (3000+2500)V

Where v is their common velocity

Momentum after collision = 5500V

Based on the law:

75000+(-37500) = 5500V

75000-37500 = 5500V

37500 = 5500V

V = 37500/5500

V = 6.82m/s

7 0

3 years ago

Earth recycles water through select all that apply

Natasha2012 [34]

Answer:

evaporation to condensation to precipitation.

6 0

3 years ago

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Compression is to crest as rarefaction is to _________.