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Stolb23 [73]
3 years ago
5

A sinusoidal wave is reflected at the surface of a medium whose properties are such that half the incident energy is absorbed. C

onsider the field that results from the superposition of the incident and the reflected wave. An observer stationed somewhere in this field finds the local electric field oscillating with a certain amplitude E. What is the ratio of the largest such amplitude noted by an observer to the smallest amplitude noted by any observer
Physics
1 answer:
kvv77 [185]3 years ago
4 0

Answer:

\frac{Ei + Er}{Ei-Er}

Explanation:

Ratio of the largest amplitude to the smallest amplitude is called voltage standing wave ratio ( along a transmission line )

<u>Determine the ratio of the largest such amplitude noted by an observer tot the smallest amplitude </u>

Expression for VSWR

VSWR =  \frac{1 + \sqrt{\frac{Pr}{Pi} } }{1 - \sqrt{\frac{Pr}{Pi} } }    where ; Pr = reflected power , Pi = Incident power

hence the ratio of the largest amplitude to the smallest amplitude

= \frac{Emax}{Emin} = \frac{Ei + Er}{Ei-Er}  where ; Ei = amplitude of incident wave, Er = amplitude of reflected wave

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0.48 cm

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4 years ago
Least count of a stop watch is 0.2 sec. The time of 20 oscillations of a pendulum is measured to be 25 sec. The max % error in m
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I hope my answer has come to your help. Thank you for posting your question here in Brainly.
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