Question

What is the mass in grams of 1.71 x 10^34 molecules of ketamine?

Answer 1

The mass of ketamine is  66.56 ×$10^{11}$ g.

Number of mole = Avogadro number / number of molecules

Avogadro number =  6.02 × $10^{23}$

Number of molecules =  1.71 ×$10^{34}$

Number of mole = 1.71 ×$10^{34}$ / 6.02 × $10^{23}$ = 0.28 ×$10^{11}$

Number of mole = given mass / molar mass

Molar mass of ketamine = 237.72 g

Number of mole = 0.28 ×$10^{11}$

Hence, given mass = Number of mole × molar mass

Given mass = 0.28 ×$10^{11}$ × 237.72 g

Given mass = 66.56 ×$10^{11}$ g

So, the mass of ketamine is  66.56 ×$10^{11}$ g.

Avogadro number is number 6.022 × 10²³ is known as Avogadro's number or Avogadro's constant. The concept of the mole can be used to convert between mass and number of particles.

Learn more about Avogadro number here:- brainly.com/question/14138110

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