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KonstantinChe [14]
2 years ago
5

In both trials, you started with the same amounts of nitrogen and oxygen atoms. In this situation, did the equilibrium amounts c

hange depending on the direction of the reaction?
Chemistry
1 answer:
sergiy2304 [10]2 years ago
7 0

Answer:

No.

Explanation:

The equilibrium amounts relatively do not change depending on the reaction, whether you started with 8 moles of NO2 or 4 moles of NO2.  

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What is a jump start that can speed up the decomposition reaction in soda
vivado [14]

Answer:

you have to shake the soda up

4 0
3 years ago
The amount of energy needed to heat 6.2 g of a substance from 50.0°C to 80.0°C is 27.4 J. What is the specific heat capacity of
taurus [48]

Answer:

The heat capacity for the sample is 0.913 J/°C

Explanation:

This is the formula for heat capacity that help us to solve this:

Q / (Final T° - Initial T°) = c . m

where m is mass and c, the specific heat of the substance

27.4 J / (80°C - 50°C) = c . 6.2 g

[27.4 J / (80°C - 50°C)] / 6.2 g = c

27.4 J / 30°C . 1/6.2g = c

0.147 J/g°C = c

Therefore, the heat capacity is 0.913 J/°C

7 0
3 years ago
Which statement(s) correctly compare the masses of protons, neutrons, and electrons? Select two options.
Ludmilka [50]

Answer:

6 Electrons r smaller than a proton or a neutron

5 0
2 years ago
Express the frequency in inverse seconds. n=4-->n=3. Can you please tell me what formulas to use, because I have like 6 more
bulgar [2K]

Answer:

  • 1.60×10¹⁴ s⁻¹

Explanation:

When an electron jumps from one energy level to a lower energy level some energy is released in the form of a photon.

The difference in energy between the two levels is the energy of the photon and that energy is related to the frequency of the photon by the Einstein - Planck equation:

  • E = hν

Where,

  • E = energy of the photon,
  • h = 6.626×10⁻³⁴ J.s, Planck constant, and
  • ν = frequency of the photon.

So, to find the frequency you must first find the energy.

The transition energy can be calculated using the formula:

  • Eₙ = - E₀ ( 1/ n²)

Where E₀ = 13.6 eV ( 1 eV = 1.602×10⁻¹⁹ Joules) and n = 1,2,3,...

So, the transition energy between n = 4 and n = 3 will be:

  • ΔE = - E₀ [ 1/4² - 1/3²] = - 13.6 eV [1/16 - 1/9] = 0.6611. . .eV

  • ΔE = 1.602×10⁻¹⁹ Joules/eV  × 0.6611... eV = 1.0591 ×10⁻¹⁹ Joules

Now you can use the Einstein - Planck equation:

  • E = hν
  • ν = E / h
  • ν = 1.0591 ×10⁻¹⁹ J / 6.626×10⁻³⁴ J.s  = 1.60×10¹⁴ s⁻¹ (rounded to 3 significant figures).
3 0
3 years ago
Read 2 more answers
Three identical flasks contain three different gases at standard temperature and pressure. Flask A contains CH4, flask B contain
erastovalidia [21]

Answer:

FLASK B WHICH CONTAINS CO2 HAS THE HIGHEST NUMBER OF MOLECULES AS IT CONTAINS THE HIGHEST MOLECULAR MASS OF 44 G/MOL.

Explanation:

Flask A contains CH4

Flask B contaims CO2

Flask C contains N2

To know the flask containing the largest number of molecules, we find the molar mass of the molecules in the flask and the largest is the one with the highest number of the relative molecular mass.

Molecular Mass of CH4 (C = 12, H =1) = ( 12 + 1*4) g/mol

= 16 g/mol

Molecular mass of CO2 (C= 12, 0= 16) = (12 + 16*2) g/mol

= 12 + 32 g/mol

= 44 g/mol

Molecular mass of N2 (N=14) = 14 * 2 g/mol

= 28 g/mol

Hence, the flask with the largest number of molecules is the flask with the highest relative molecular mass. The highest molecular mass is 44 g/mol and it is for the gas CO2 in Flask B.

So therefore, Flask B has the highest number of molecules in it.

4 0
2 years ago
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