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KonstantinChe [14]

2 years ago

5

In both trials, you started with the same amounts of nitrogen and oxygen atoms. In this situation, did the equilibrium amounts c

hange depending on the direction of the reaction?

1 answer:

sergiy2304 [10]2 years ago

7 0

Answer:

No.

Explanation:

The equilibrium amounts relatively do not change depending on the reaction, whether you started with 8 moles of NO2 or 4 moles of NO2.

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What SI Unit would best be used to express the height of your classroom ceiling?

ivolga24 [154]

SI unit of length - meters

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3 years ago

Consider the following mechanism: O3 => O2 + O NO + O => NO2 What is the role of O2? A. intermediate B. catalyst C. reacta

Daniel [21]

Answer:

The correct answer is option D.

Explanation:

Step 1: $O_3\rightarrow O_2+O$

Step 2: $NO+O\rightarrow NO_2$

Overall reaction can be determined by adding all the reactions of mechanism:

$O_3+NO\rightarrow O_2+NO_2$

Reactants in an overall reaction = $O_3\& NO$

Products in an overall reaction = $O_2\& NO_2$

According to question , the role of oxygen gas is product.

5 0

3 years ago

Which type of bond is present in hydrogen sulfide (H2S)? The table of electronegativities is given

LuckyWell [14K]

Bonds formed between atoms can be classified as ionic and covalent

Ionic bonds are formed between atoms that have a high difference in the electronegativity values.

In contrast, bonds formed between atoms that have a difference in electronegativity lower than the ionic counterparts are polar covalent bonds. If the atoms have very similar electronegativities, they form non-polar covalent bonds.

In H2S, the S atom is bonded to 2 H atoms. The electronegativity of H = 2.2 and S= 2.56. Since the difference is not high the bond formed will be covalent (polar covalent).

7 0

3 years ago

Read 2 more answers

What causes red blood cells to become sickle-shaped in a person with sickle

White raven [17]

Answer:

A. Inheriting a specific gene

Explanation:

I hope this helps! ^^

☁️☁️☁️☁️☁️☁️☁️

6 0

2 years ago

Read 2 more answers

What concentrations of acetic acid (pKa = 4.76) and acetate would be required to prepare a 0.15 M buffer solution at pH 5.0? Not

Leni [432]

Answer:

Acetic acid 0,055M and acetate 0,095M.

Explanation:

It is possible to prepare a 0,15M buffer of acetic acid/acetate at pH 5,0 using Henderson-Hasselblach formula, thus:

pH = pka + log₁₀ [A⁻]/[HA] <em>-Where A⁻ is acetate ion and HA is acetic acid-</em>

Replacing:

5,0 = 4,76 + log₁₀ [A⁻]/[HA]

<em>1,7378 = [A⁻]/[HA] </em><em>(1)</em>

As concentration of buffer is 0,15M, it is possible to write:

<em>[A⁻] + [HA] = 0,15M </em><em>(2)</em>

Replacing (1) in (2):

1,7378[HA] + [HA] = 0,15M

2,7378[HA] = 0,15M

[HA] = 0,055M

Thus, [A⁻] = 0,095M

That means you need <em>acetic acid 0,055M</em> and <em>acetate 0,095M</em> to obtain the buffer you need.

i hope it helps!

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3 years ago