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Juliette [100K]
3 years ago
6

Please help due in 5 minutes

Chemistry
2 answers:
Mrac [35]3 years ago
4 0
Number 1 is a and number 2 is none
mezya [45]3 years ago
3 0
1 a 2 none
334)(.)4;,(?&&?7&
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A gas sample in a rigid container at 455 K is brought to STP (273K and 1 atm). What was the original pressure of the gas in mmHg
Molodets [167]
1) V(CH₄) = 0,376 L.T(CH₄) = 304 K.p(CH₄) = 1,5 atm 101325 Pa/atm = 151987,5 Pa = 151,9875 kPa.R = 8,314 J/K·mol.Use ideal gas law: p·V = n·R·T.n(CH₄) = p · V ÷ R · T.n(CH₄) = 151,9875 kPa · 0,376 L ÷ 8,314 J/K· mol · 304 K.n(CH₄) = 0,0226 mol.V(CH₄) = n(CH₄) · Vm.V(CH₄) = 0,0226 mol · 22,4 dm³/mol.V(CH₄) = 0,506 dm³ = 0,506 L.
2) V(SO₂) = 5,2 L.p(SO₂) = 45,2 atm = 45,2 atm · 101,325 kPa/atm = 4579,89 kPa.T(SO₂) = 293 K.R = 8,314 J/K·mol.Use ideal gas law: p·V = n·R·T.n(SO₂) = p · V ÷ R · T.n(SO₂) = 4579,89 kPa · 5,2 L ÷ 8,314 J/K· mol · 293 K.n(CH₄) = 9,77 mol.There is not enogh SO₂, 225 mol - 9,77 mol = 215,23 mol is needed.
3) p(He) = 3,50 atm · 101,325 kPa/atm = 354,63 kPa.V(He) = 4,00 L.n(He) = 0,410 mol.R = 8,314 J/K·mol.Use ideal gas law: p·V = n·R·T.T = p · V ÷ R · n.T(He) = 354,63 kPa · 4,00 L ÷ 8,314 J/K· mol · 0,410 mol.T(He) = 416,14 K.n - amount of substance.
4) p(Ar) = 1,00 atm · 101,325 kPa/atm = 101,325 kPa.V(Ar) = 3,4 L.T(Ar) = 263 K.R = 8,314 J/K·mol.Use ideal gas law: p·V = n·R·T.n(Ar) = p · V ÷ R · T.n(Ar) = 101,325 kPa · 3,4 L ÷ 8,314 J/K· mol · 263 K.n(Ar) = 0,157 mol.n(Ar) = 0,157 mol + 2,5 mol = 2,657 mol.p(Ar) = 2,657 mol · 8,314 J/K· mol · 263 K ÷ 3,4 L.p(Ar) = 1708,74 kPa.
6 0
4 years ago
Balance the chemical equation by indicating the number of each species in the appropriate blanks. For this exercise, indicate co
ch4aika [34]

Answer:

3 Fe (s) + 4 H2O (l) -----> Fe3O4 (s) + 4 H2 (g)

Explanation:

your question is not completed , perhaps the question is similar to this solution, you can use it .

The balanced equation is

3 Fe (s) + 4 H2O (l) -----> Fe3O4 (s) + 4 H2 (g)

Explanation: In order to balance an equation we must ensure that the number of atoms of each species on right side of the arrow must be equal to the number of atoms of each species on left side of the arrow.

8 0
3 years ago
What does the symbol ka mean in chemistry?
Dmitry_Shevchenko [17]
 <span>Ka is an equilibrium constant for the partial ionization of "weak" acids in water.</span>
4 0
4 years ago
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Based on the thermodynamic properties provided for water, determine the energy change when the temperature of 0.750 kg of water
Vlad [161]

The energy change when the temperature of 0.750 kg of water decreased from 123 °C to 23.0 °C is  -313.5 kJ.

In this problem, we are dealing with specific heat which is referred to as the sum of heat per unit mass required to raise the temperature by one degree Celsius.Since we know the boiling point of water is 100°C, at 123°C, the water is steam.

The formula we are referring to for  calculating the heat energy Q

Q= m C ΔT

where m is the mass of water which is equal to 0.750  Kg, then

C is the specific heat of water equal to  4180 J/Kg °C and

ΔT is the change in temperature which is (23-123)= -100°C

So, assembling those desired values on the formula we get,

Q= 0.750 (4180) (-100)

Q=-313500

 = -313.5 kJ

To know more about specific heat refer to the link brainly.com/question/13163208?referrer=searchResults.

#SPJ1

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Air with less than 19.5% oxygen cannot support human life. How many moles of oxygen would the caisson if the percent of oxygen i
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Are we adding the percent?
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