Answer:
The speed of the two cars after coupling is 0.46 m/s.
Explanation:
It is given that,
Mass of car 1, m₁ = 15,000 kg
Mass of car 2, m₂ = 50,000 kg
Speed of car 1, u₁ = 2 m/s
Initial speed of car 2, u₂ = 0
Let V is the speed of the two cars after coupling. It is the case of inelastic collision. Applying the conservation of momentum as :
V = 0.46 m/s
So, the speed of the two cars after coupling is 0.46 m/s. Hence, this is the required solution.
Answer:
a)
b)
c)
d)
Explanation:
Given:
mass of the player,
mass of the ball,
initial velocity of the player,
initial velocity of the ball,
a)
<u>Case:</u> When the player and the ball are moving in the same direction.
where:
total mass after the player catches the ball
v = final velocity of the system
b)
Initial kinetic energy of the system:
Final kinetic energy of the system:
∴Change in kinetic energy
c)
<u>Case:</u> When the player and the ball are moving in the opposite direction.
d)
Final kinetic energy in this case:
∴Change in kinetic energy:
Given data
*The mass of Bruce is m_1 = 45 kg
*The initial velocity of the Bruce is u_1 = 2 m/s
*The mass of the biff is m_2 = 90 kg
*The initial velocity of the Biff is u_2 = -7 m/s
*The final velocity of the first glider is v_2 = -1 m/s
According to the law of conservation of linear momentum, the total linear momentum of a system remains constant
Applying the law of conservation of momentum as
Substitute the known values in the above expression as
Hence, the speed of the bruce knock backwards is v_1 = -10 m/s