What is the product of x+2 and x-7? Write your answer in standard form.

In February, Campus Cycle Repair had income from sales of $16,000. Expenses for the month included: rent, $1,250; utilities, $45

djyliett [7]

Answer:

Profit $5700

Step-by-step explanation:

To find loss/profit you subtract the expenses from the total income

Income from sales= $16000

Franchise fee= 5% of sales income

$=\frac{5}{100} *16000=800$

Rent=$1250

Utilities=$450

Wages=$4800

insurance=$300

supplies=$2700

Total expenses

=$1250+$450+$4800+$300+$2700+$800=$10300

Total income

=$16000

Profit

=$16000-$10300=$5700

5 0

3 years ago

How do I find the volume of an L-block?

DIA [1.3K]

First break the L into two rectangular prisms and then find the volume for each prism. Then add those two volumes together to get the L.

5 0

3 years ago

Read 2 more answers

In 2003 the population of Africa was about 7.7 million people which is 2million more than 3 times the population in 1950

shtirl [24]

The answer to the question is 1.9 million in 1950.

5 0

3 years ago

Find all roots: x^3 + 7x^2 + 12x = 0 Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

Solution:

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

Therefore, the two roots are:

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0

3 years ago

A rectangular pool contains 920 cubic meters of water. the pool is .4 meter deep and 100 meters wide. How long is the pool?

LekaFEV [45]

Hi there,

Sol:
Length of the swimming pool = 260 m
Breadth of the swimming pool = 140 m

Let the height of the water in the swimming pool after pouring water be h meters.

Volume of the water poured = 54600 m3

l x b x h = 54600
260 x 140 x h = 54600
h = (54600) / (260 x 140)
h = 1.5 m = 150 cm

Hope it helps

5 0

3 years ago