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OLga [1]
3 years ago
8

g Two balls are dropped in such a way that each ball is equally likely to fall into any one of four holes. Both balls may fall i

nto the same hole. Let X denote the number of unoccupied holes at the end of the experiment. What is Var X  ?
Mathematics
1 answer:
faust18 [17]3 years ago
5 0

Answer:

0.5

Step-by-step explanation:

X=[3,2]

mean= 5/2

(X-μ)²= [0.25, 0.25]

Var X =Σ (X-μ)²/(n-1)

Var X = (0.25+0.25)/(2-1)

Var X = 0.5

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Task 1:
OleMash [197]

Answer:

maximum height is 4.058 metres

Time in air = 0.033 second

Step-by-step explanation:

Given that the equation height h

h = -212t^2 + 7t + 4

What is the toy's maximum height?

Let us assume that the equation is a perfect parabola

Time t at Maximum height will be

t = -b/2a

Where b = 7 and a = - 212

t = -7/ - 212 ×2

t = 7/ 424 = 0.0165s

Substitute t in the main equation

h = - 212(7/424)^2 + 7(7/424) + 4

h = - 0.05778 + 0.115567 + 4

h = 4.058 metres

Therefore the maximum height is 4.058 metres

How long is the toy in the air?​

The object will go up and return to the ground.

At ground level, h = 0

-212t^2 + 7t + 4 = 0

212t^2 - 7t - 4 = 0

You can factorize the above equation and pick the positive time t since time can't be negative

Or

Since we have assumed that it's a perfect parabola,

Total time in air = (-b/2a) × 2

Time in air = 0.0165 × 2 = 0.033 s

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3 years ago
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It’s 4 so ye it’s ez so ye bye
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