A. what is the e value for the oxidation of cytochrome c by the cua redox center in complex iv when the ratio of cyt c (fe3 ) /c
1 answer:
You might be interested in
Answer: 3M
Explanation: Molarity : It is defined as the number of moles of solute present in one liter of solution.
Formula used :
where,
n = moles of solute = 0.6 moles
= volume of solution in ml= 200 ml
Now put all the given values in the formula of molarity, we get
Therefore, the molarity of solution will be 3M.
Solution :
It is given that :
Weight of the antacid tablet = 5.4630 g
4.3620 gram of antacid is crushed and is added to the stomach acid of 200 mL and is reacted.
25 mL of the stomach acid that is partially neutralized required 13.6 mL of NaOH to be titrated for a red end point.
27.7 mL of solution is equivalent to
of the original stomach acid. Therefore, 13.6 mL of NaOH will take x
= 12.27 ml of the original stomach acid.
Answer:
Explanation:
In this case, we have to remember that relationship between the <u>avogadro's number</u> and the "mol" concept:
With this in mind, we can do the <u>first conversion</u>:
Now, if we calculate the molar mass of . <u>The atomic mass of O is 16 g/mol and the atomic mass of H is 1 g/mol</u>, so:
(16*1)+(1*2)= 18 g/mol
In other words, , so:
I hope it helps!