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12345 [234]
3 years ago
9

What liquid doesn't belong in a science laboratory?

Chemistry
1 answer:
OLEGan [10]3 years ago
3 0
Drinks don't belong in science laboratories
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I need an answer now please asap and you will me marked brainiest please it's missing I need it now.
Phoenix [80]

Answer:

Just put 1 in the boxes

Explanation:

3 0
2 years ago
Read 2 more answers
What is per cent by mass of Na2CO3 in a 1.0 molal aqueous solution ?
aivan3 [116]
Hello!

We have the following data:

MM (Molar mass of Na2CO3) 
Na = 2*23 = 46 u
C = 1*12 = 12 u
O = 3*16 = 48 u
----------------------
MM (Molar mass of Na2CO3) = 46+12+48 = 106 g/mol
n (mol number) = 1 mol
m1 (mass of the solute) = ?

n =  \dfrac{m_1}{MM}

1\:mol\!\!\!\!\!\!\!\!\!\!\!\dfrac{\hspace{0.6cm}}{~}=  \dfrac{m}{106\:g/mol\!\!\!\!\!\!\!\!\!\!\!\dfrac{\hspace{0.6cm}}{~}}

m_1 = 1*106

\boxed{m_1 = 106\:g}\Longleftarrow(solute\:mass)

So if we have the dissolution in a liter (m2 - mass of solvent), that is 1000g , then the total mass of the solution (m) will be:

m\:(solution\:mass) = m_1\:(solute\:mass) + m_2\:(solvent\:mass)

m = 106\:g+1000\:g

\boxed{m = 1106\:g}\Longleftarrow(solution\:mass)

<span>Now, let's find the percentage in mass (% m / m), let's see:
</span>
\%(m/m) =  \dfrac{m_1}{m}*100

\%(m/m) = \dfrac{106}{1106}*100

\%(m/m) = \dfrac{10600}{1106}

\%(m/m) = 9.58408...\to\:\boxed{\boxed{\%(m/m) \approx 9.6}}\end{array}}\qquad\checkmark

Answer: B) 9.6

I Hope this helps, greetings ... DexteR!
5 0
3 years ago
Imagine a 10 kg block moving with a velocity of 20/ms to the left calculate the kinetic energy of this block
tino4ka555 [31]

Answer:

KE = 1/2 mv^2=0.5x 10 X 20^2=  800

Explanation

4 0
3 years ago
Acetic acid (ch3cooh) and trifluoroacetic acid (cf3cooh) are shown by these particulate models. the ka for trifluoroacetic acid
V125BC [204]

Answer:

See explanation

Explanation:

If we look at the models, we will see that the three fluorine atoms in CF3COOH are attached to the carbon that is next to the -COOH group.

As a result of the electron withdrawing effect of the three fluorine atoms, CF3COOH  is much more acidic (104 times more acidic) than CH3COOH. This is reflected in the value of the Ka for each acid.

This electron withdrawing effect of the three fluorine atoms also stabilizes CF3COO- much more than CH3COO-.

3 0
3 years ago
Write and balance the equation for the complete combustion of ethane, C2H6.
Juliette [100K]

Answer:

C2H6 + 7/2O2 ....... 2CO2 + 3H2O

8 0
3 years ago
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