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ioda
3 years ago
13

The complete combustion of 1.00 kg of coal releases about 3.0 x 10E7 J of energy. The conversion of 1.00 kg of mass into energy

is equivalent to the burning of how many metric tonnes of coal?
Chemistry
2 answers:
zalisa [80]3 years ago
3 0

Answer: 0.001 metric tonnes

Explanation:

According to Einstein equation, Energy and mass are inter convertible.

E=mc^2

E=  Energy

m = mass

c= speed of light

Given : Complete combustion of 1.00 kg of coal releases about 3.0\times 10^7 J of energy.

Given mass: 1 kg

Converting kg to metric ton using the conversion factor:

1 kg=0.001 metric tonnes

Thus 1 kg of coal would also be equal to 0.001 metric tonnes.

yKpoI14uk [10]3 years ago
3 0

Answer:

qrqwrqewq

Explanation:

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photoshop1234 [79]

Answer:

3-methylhexane

Explanation:

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4 0
2 years ago
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(a) Given that Ka for acetic acid is 1.8 X 10^-5 and that for hypochlorous acid is 3.0 X 10^-8, which is the stronger acid? (b)
Gala2k [10]

Answer:

HOAc is stronger acid than HClO

ClO⁻ is stronger conjugate base than OAc⁻

Kb(OAc⁻) = 5.5 x 10⁻¹⁰

Kb(ClO⁻) = 3.3 x 10⁻⁷

Explanation:

Assume 0.10M HOAc => H⁺ + OAc⁻  with Ka = 1.8 x 10⁻⁵

=> [H⁺] = √Ka·[Acid] =√(1.8 x 10⁻⁵)(0.10) M = 1.3 x 10⁻³M H⁺

Assume 0.10M HClO => H⁺ + ClO⁻ with Ka = 3 x 10⁻⁸

=> [H⁺] = √(3 x 10⁻⁸)(0.10)M = 5.47 x 10⁻⁵M H⁺

HOAc delivers more H⁺ than HClO and is more acidic.

Kb = Kw/Ka, Kw = 1 x 10⁻¹⁴

Kb(OAc⁻) = 5.5 x 10⁻¹⁰

Kb(ClO⁻) = 3.3 x 10⁻⁷

4 0
3 years ago
How can you explain what happened?
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Answer:

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Explanation:

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3 0
2 years ago
1. What pressure would be exerted by 46.0grams of hydrogen gas placed into a 3.00 L container at
dlinn [17]

Answer:

187.34 atm

Explanation:

From the question,

PV = nRT.................. Equation 1

Where P = Pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.

make P the subject of the equation

P = nRT/V.............. Equation 2

n = mass(m)/molar mass(m')

n = m/m'............... Equation 3

Substitute equation 3 into equation 2

P = (m/m')RT/V............ Equation 4

Given: m = 46 g, T = 25°C = (25+273) = 298 K, V = 3.00 L

Constant: m' = 2 g/mol, R = 0.082 atmL/K.mol

Substitute these values into equation 4

P = (46/2)(0.082×298)/3

P = (23×0.082×298)/3

P = 187.34 atm

3 0
2 years ago
-3 × 4=? ....................​
blagie [28]

Answer:

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Explanation:

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8 0
3 years ago
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