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BlackZzzverrR [31]
3 years ago
10

What is the average mass of an electron? A. 1 amu B. 1,837 amu C. 1/1,837

Chemistry
1 answer:
diamong [38]3 years ago
3 0

Answer:

C. 1/1,837

Explanation:

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faust18 [17]

Answer:

D) It has a different unit than atomic mass.

4 0
3 years ago
What mass of hydrogen is required to react with 24.7 g of nitrogen?
yaroslaw [1]

Answer:

10.80 g of H2

Explanation:

As per the equation, let us calculate the mole ratio. N2+3H2→2NH3. As per the equation one mole of nitrogen

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3 years ago
A student dissolves 73 g of sodium nitrate, NaNO3, in 100 mL of water and observes a clear, colorless
ohaa [14]
I 90% sure that it would be supersaturated
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2 years ago
How is 0.00036 written in scientific notation?
natta225 [31]
3.6 x 10^-4
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4 0
3 years ago
What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha
sladkih [1.3K]

Answer:

The mean free path = 2.16*10^-6 m

Explanation:

<u>Given:</u>

Pressure of gas P = 100 kPa

Temperature T = 300 K

collision cross section, σ = 2.0*10^-20 m2

Boltzmann constant, k = 1.38*10^-23 J/K

<u>To determine:</u>

The mean free path, λ

<u>Calculation:</u>

The mean free path is related to the collision cross section by the following equation:

\lambda =\frac{1}{n\sigma }------(1)

where n = number density

n = \frac{P}{kT}-----(2)

Substituting for P, k and T in equation (2) gives:

n = \frac{100,000 Pa}{1.38*10^{-23} J/K*300K} =2.42*10^{25}\  m^{3}

Next, substituting for n and σ in equation (1) gives:

\lambda =\frac{1}{2.42*10^{25}m^{-3}* .0*10^{-20}m^{2}}=2.1*10^{-6}m

6 0
3 years ago
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