All categories

1 year ago

Explain why there is total internal reflection in an optical fibres

1 answer:

6 0

The optical fibers are thin, thus, the light entering from one side of the wire surface has more chances to reflect back from the inside surface due to the larger angle of incidence.

The angle of the strike is large due to the small size of the wire and this angle is greater than the critical angle.

As the angle of the incident light on the inside surface is greater than the critical angle, thus, the total internal reflection of the takes place.

Hence, there are more chances of total internal reflection of light inside the optical fiber wire than the emergence of light through the wire.

You might be interested in

Which of the following classifications of matter includes materials that can no longer be identified by their individual propert

lozanna [386]

The correct answer is B, I think

hope this helps

3 0

3 years ago

Read 2 more answers

Determine the speed

Paraphin [41]

Calculating the average speed is simple using the formula <span>speed = distance/time</span>

3 0

4 years ago

007 (part 1 of 2) 1.0 points

levacccp [35]

Answer:

a) The angle of refraction is approximately 34.7

b) The angle the light have to be incident to give an angle of refraction of 90° is approximately 53.42°

Explanation:

According to Snell's law, we have;

$\dfrac{n_1}{n_2} = \dfrac{sin (\theta_2)}{sin (\theta_1)}$

The refractive index of the glass, n₁ = 1.66

The angle of incident of the light as it moves into water, θ₁ = 27.2°

a) The refractive index of water, n₂ = 1.333

Let θ₂ represent the angle of refraction of the light in water

By plugging in the values of the variables in Snell's Law equation gives;

$\dfrac{1.66}{1.333} = \dfrac{sin (\theta_2)}{sin (27.2^{\circ})}$

$sin (\theta_2) = sin (27.2^{\circ}) \times \dfrac{1.66}{1.333} \approx 0.5692292265$

θ₂ = arcsin(0.5692292265) ≈ 34.7°

The angle of refraction of the light in water, θ₂ ≈ 34.7°

b) When the angle of refraction, θ₂ = 90°, we have;

$\dfrac{1.66}{1.333} = \dfrac{sin (90^{\circ})}{sin (\theta_1)}$

$sin (\theta_1) = \dfrac{sin (90^{\circ})}{\left( \dfrac{1.66}{1.333}\right)} = sin (90^{\circ}) \times \dfrac{1.333}{1.66} \approx 0.803$

θ₁ ≈ arcsin(0.803) ≈ 53.42°

The angle of incident, θ₁, that would give an angle of refraction of 90° is θ₁ ≈ 53.42°

3 0

3 years ago

A woman has a mass of 55 kg on earth. what would be the women's weight on the moon? (The moon’s gravity is 1.6 N).

Alex17521 [72]

Answer:

i dont know the answer sorry have a good day

Explanation:

hsjsjdkdkdkdkdkdk

8 0

3 years ago

A 2.50-kg stone is dropped from rest at a height of 3.75 m. What impulse does gravity impart to this stone from the instant it i

Art [367]

Answer:

22.3Ns

Explanation:

Hi!

To solve this exercise follow the steps below.

1. Find the weight of the stone by multiplying the gravity (9.8m / s ^ 2) by the mass.

W=mg

m=mass=2.5kg

g=gravity=9.8m / s ^ 2

W=(2.5)(9.8)=25.5N

2. Find the time it takes for the stone to touch the ground using the kinematic equation for constant acceleration.

Vf=Vo+a.t

y= VoT+\frac{1}{2}gt^{2}

Where

Vo = Initial speed =0

T = time

g=gravity=9.8m/s^2

Y= height= 3.75m

solving for time

$2y=gt^2\\t=\sqrt{ \frac{2y}{g} }=\sqrt{ \frac{2(3.75)}{9.8} }=0.87s$

3. For a constant force such as weight, the impulse is calculated as the product between force and time.

I=wt

I=(25.5N)(0.87S)=22.3Ns

5 0

3 years ago