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Bad White [126]

3 years ago

5

If an electric wire is allowed to produce a magnetic field no larger than that of the Earth (0.50 x 10-4 T) at a distance of 15

cm from the wire, what is the maximum current the wire can carry? Express your answer using two significant figures.

1 answer:

ser-zykov [4K]3 years ago

3 0

Answer:

$I = 37.5\ A$

Explanation:

Given,

Magnetic field,B = 0.5 x 10⁻⁴ T

distance,r= 15 cm = 0.15 m

Current = ?

Using Ampere's law of magnetic field

$B = \dfrac{\mu_0I}{2\pi r}$

$I= \dfrac{B (2\pi r)}{\mu_0}$

$I= \dfrac{0.5\times 10^{-4}\times (2\pi \times 0.15)}{4\pi \times 10^{-7}}$

$I = 37.5\ A$

Current in the wire is equal to $I = 37.5\ A$

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A doctor has a patient blow on one side of a U-shaped tube that is partially filled with water and has a ball floating on the ot

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