All categories

1 year ago

A sample of water has a volume of 560

Chemistry

1 answer:

Ymorist [56]1 year ago

6 0

Explanation:

density=mass÷volume

density= 560÷560

density= 1 g/mL

You might be interested in

HELP PLEASEEEE

kifflom [539]

Explanation:

So first find out the moles. The percentage is out of 100 so just convert the percentage into mass by just changing the sign.

Ga = 55g/69.7 = 0.789 moles

F=45g/19 = 2.37 moles

Then divide by smallest value to find out the formula

Ga=0.789÷0.789= 1

F=2.37÷0.789 = 3

GaF3

hope this helps:)

6 0

2 years ago

What is the mass of 6.02 x 1022 atoms of Xenon? HELP!!!!!

il63 [147K]

So 6.02*10^22 is avogadro constant, which is the amount of atoms in one mole. If you look Xenon up in the periodic table you will find it's mass given <span>131,293, which is grams per 1 mole.

</span>

8 0

3 years ago

Name a type of asteroid and give a description.

IceJOKER [234]

Answer:

S-type or silaceous asteroids are made up primarily of stony materials and nickel-iron. They inhabit the inner Asteroid Belt. M-type, or metallic, are made up mostly of nickel-iron, and are found in the middle region of the Asteroid Belt

Explanation:

3 0

4 years ago

Read 2 more answers

An unknown compound was found to have a percent composition as follows: 47.0%, 14.5 carbon, and 38.5 oxygen. What is its empiric

shusha [124]

KCO₂

K₂C₂O₄

Explanation:

Given parameters:

Percent composition:

K = 47%

C = 14.5%

O = 38.5%

Molar mass of compound = 166.22g/mol

Unknown:

Empirical formula of compound = ?

Molecular formula of compound = ?

Solution:

The empirical formula of a compound is its simplest formula. Here is how to solve for it:

K C O

Percent

composition 47 14.5 38.5

Molar mass 39 12 16

Number

of moles 47/39 14.5/12 38.5/16

moles 1.205 1.208 2.4

Dividing

by smallest 1.205/1.205 1.208/1.205 2.4/1.205

1 1 2

Empirical formula KCO₂

Molecular formula

This is the actual combination of the atoms:

Molecular formula = ( empirical formula of KCO₂)ₙ

Molar mass of empirical formula = 39 + 12 + 2(16) = 83g/mol

n factor = $\frac{true molecular mass}{molar mas of empirical formula}$

n factor = $\frac{166.22}{83}$ = 2

Molecular formula of compound = ( KCO₂)₂ = K₂C₂O₄

Learn more:

Empirical formula brainly.com/question/2790794

#learnwithBrainly

6 0

4 years ago

In two or more complete sentences explain how to balance the chemical equation and classify its reaction type.

Ierofanga [76]

This is a double replacement reaction. To balance the equation, you can not change the subscript because it will fully change the equation. Instead you change the coefficient infront of the element.

4 NaI + 1 Pb(SO4)2 —> 1 PbI4 +2 Na2SO4

8 0

3 years ago