98.079 g/mol
Is that what ur asking?
Specific heat of Aluminium is 0.89 g/J
Explanation:
Step 1 :
Specific heat of a substance is the energy absorbed by a substance of unit mass when its temperature increases by one degree.
Energy Absorbed = Specific Heat * Mass of the substance * Temperature Difference
Step 2 :
It is given that 120 g sample absorbs 9612 J energy when the temperature increases from 298K to 388K.
Temperature Difference = 388 K - 298 K = 90 K
Step 3:
Specific Heat = (Energy Absorbed) ÷ (Mass of the substance * Temperature Difference)
Specific Heat = 9612 ÷ (120 * 90) = 0.89 grams / Joule
Step 4:
Answer:
Specific heat of Aluminium is 0.89 g/J
Answer:
0.5m/s2
Explanation:
Data obtained from the question include:
u (initial velocity) = 0m/s
v (final velocity) = 30m/s
t (time) = 1min = 60secs
a (Acceleration) =?
a = v — u/t
a = 30—0 / 60
a = 30/60
a = 0.5m/s2
