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gogolik [260]
3 years ago
11

Use the concept of electron configurations to explain why the number of valence electrons in metals tends to be less than the nu

mber in most nonmetals.
Chemistry
1 answer:
HACTEHA [7]3 years ago
3 0

Answer:

The electronic configuration uses the principle of the K,L,M,N shells to arrange electrons in the shells of elements. The K shell which is the first shell can only accommodate two electrons while the rest shells can accommodate a maximum of 8 electrons. Metals and nonmetals have atomic numbers which tells us the amount of electrons they contain in their neutral state.

For example the metal  Sodium (Na) has an atomic number of 11.The electronic configuration will be; 2,8,1 .

The non metal Chlorine has an atomic number of 17. The electron configuration will be 2,8,7

The valence shell refers to the last shell of an atom.

We can see from the electronic configurations that sodium has 1 electron in its valence shell, while chlorine has 7 electrons in its valence shell. Generally non-metals gain electrons because of the large number of electrons in their valence shell and metals lose electrons due to the fewer number of electrons in their valence shell

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Answer:

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Plants undergo photosynthesis to produce glucose according to the reaction below. What mass of water is required to produce 5.0g
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Answer:

option a) 3 g

Explanation:

mass of Glucose = 5 g

Mass of H₂O = ?

Reaction Given:

                   6CO₂ + 6H₂O ----> C₆H₁₂O₆ + 6O₂

Solution:

First we have to find mass of glucose from balanced reaction.

So,

Look at the reaction

                        6CO₂ + 6H₂O -------> C₆H₁₂O₆ + 6O₂

                                     6 mol               1 mol

As 6 mole of water (H₂O) give 1 mole of Glucose (C₆H₁₂O₆ )

Convert moles to mass

molar mass of C₆H₁₂O₆  = 6(12) + 12(1) + 6(16)

molar mass of C₆H₁₂O₆  = 72 + 12 + 96

molar mass of C₆H₁₂O₆= 180 g/mol

molar mass of H₂O = 2(1) + 16 = 18 g/mol

Now

             6CO₂      +  6H₂O          --------->     C₆H₁₂O₆   +    6O₂

                              6 mol (18 g/mol)           1 mol (180 g/mol)

                                  108 g                            180 g

108 g of water (H₂O) produce 180 g of glucose (C₆H₁₂O₆)

So

if 108 g of water (H₂O) produce 180 g of glucose (C₆H₁₂O₆) so how many grams of water (H₂O) will be required to produce 5 g of glucose (C₆H₁₂O₆).

Apply Unity Formula

               108 g of water (H₂O) ≅ 180 g of glucose (C₆H₁₂O₆)

                X g of water (H₂O) ≅ 5 g of glucose (C₆H₁₂O₆)

Do cross multiply

                     mass of water (H₂O) = 108 g x 5 g / 180 g

                     mass of water (H₂O) = 3 g

So 3 g of water is required to produce 5 g of glucose.  

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