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gogolik [260]
3 years ago
11

Use the concept of electron configurations to explain why the number of valence electrons in metals tends to be less than the nu

mber in most nonmetals.
Chemistry
1 answer:
HACTEHA [7]3 years ago
3 0

Answer:

The electronic configuration uses the principle of the K,L,M,N shells to arrange electrons in the shells of elements. The K shell which is the first shell can only accommodate two electrons while the rest shells can accommodate a maximum of 8 electrons. Metals and nonmetals have atomic numbers which tells us the amount of electrons they contain in their neutral state.

For example the metal  Sodium (Na) has an atomic number of 11.The electronic configuration will be; 2,8,1 .

The non metal Chlorine has an atomic number of 17. The electron configuration will be 2,8,7

The valence shell refers to the last shell of an atom.

We can see from the electronic configurations that sodium has 1 electron in its valence shell, while chlorine has 7 electrons in its valence shell. Generally non-metals gain electrons because of the large number of electrons in their valence shell and metals lose electrons due to the fewer number of electrons in their valence shell

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Answer:

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3 years ago
What type of chemical reaction is CaCaI2 + F2 = CaF2 + CI2
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Answer:

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3 years ago
A laboratory analysis of a sample finds it is composed of 38.8% carbon, 16.2% hydrogen, and 45.1% nitrogen. What is its empirica
Sladkaya [172]

Answer: The empirical formula for the given compound is CH_5N

Explanation : Given,

Percentage of C = 38.8 %

Percentage of H = 16.2 %

Percentage of N = 45.1 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 38.8 g

Mass of H = 16.2 g

Mass of N = 45.4 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{38.8g}{12g/mole}=3.23moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{16.2g}{1g/mole}=16.2moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{45.4g}{14g/mole}=3.24moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.23 moles.

For Carbon = \frac{3.23}{3.23}=1

For Hydrogen  = \frac{16.2}{3.23}=5.01\approx 5

For Oxygen  = \frac{3.24}{3.23}=1.00\approx 1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 1 : 5 : 1

Hence, the empirical formula for the given compound is C_1H_5N_1=CH_5N

3 0
3 years ago
pressure has little effect on the solubility of liquids and solids because they are almost incompressible. True or False
slavikrds [6]

Pressure has little effect on the solubility of liquids and solids because they are almost incompressible True.

Liquids and solids show little change in solubility with changes in pressure. As expected, gases increase in solubility with increasing pressure. Henry's Law states that the solubility of a gas in a liquid is directly proportional to the pressure of that gas above the surface of the solution.

External pressure has little effect on liquid and solid solubility. In contrast, the solubility of a gas increases as the partial pressure of the gas above the solution increases.

Solubility is a measure of the concentration of dissolved gas particles in a liquid and is a function of gas pressure. Increasing the gas pressure increases the number of collisions and increases the solubility, and decreasing the pressure decreases the solubility.

Learn more about pressure here : brainly.com/question/28012687

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5 0
1 year ago
The specific heat of copper is 0.093 cal/g0C. Calculate the temperature change that occurs if 28 g of copper at 25 0C absorbs 58
Umnica [9.8K]

Answer:

22.27 °C = ΔT

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m × c × ΔT

Given data:

mass = 28 g

heat absorbed = 58 cal

specific heat of copper =  0.093 cal/g .°C

temperature change =ΔT= ?

Solution:

Q = m × c × ΔT

58 cal = 28 g × 0.093 cal /g.°C × ΔT

58 cal = 2.604 cal.°C × ΔT

58 cal / 2.604 cal .°C = ΔT

22.27 °C = ΔT

5 0
3 years ago
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