Answer:
Experiments to determine mechanisms involve looking at indirect evidence to help support or disprove a proposed mechanism.
Most intermediates are not typically isolated to determine reaction mechanisms.
Carbocations are very reactive and are typically not isolated for analysis.
Scientists can prove that a specific mechanism exists.
Evidence of intermediates sometimes can be seen using techniques such as nuclear magnetic resonance spectroscopy
Explanation:
The study of reaction mechanism and chemical kinetics often form the main thrust of study in organic, inorganic and physical chemistry.
We often want to know the actual processes involved in the conversion of one specie to another. Unfortunately, this information may have to be obtained indirectly by certain chemical reactions or by the use of new instrumental methods such as nuclear magnetic resonance spectroscopy.
Many organic reactions have carbocation intermediates. These carbocations are relatively short-lived and are transient intermediates which are rarely isolated unless they are isolated in a molecular cage using a macromolecule or in superacids.
By intensive study, scientists can proof or disprove the authenticity of any proposed mechanism.
We must know that a transition state has partial bonds. It is often an extremely short-lived specie which cannot be isolated.
The prefix 'di' means two. Hence two atoms make up a diatomic molecule.
Hope this helps!
Explanation:
Water can be purified from through...
Filtration - This involves the use of filter paper to remove solid objects found in water.
Boiling - This involves keeping water at 100 deg celcius for a while through application of heat and this kills microorganisms in the water.
Addition of alum - Alum causes very fine and small particles that are suspending in water to stick together making them large enough to be removed through filtration.
Chemicals used in water treatment...
Chlorine - Chlorine is used to kill bacteria, viruses and other disease causing pathogens found in water
That's all I know...
Answer:
The frequency of photon is 0.75×10¹⁵ s⁻¹.
Explanation:
Given data:
Energy of photon = 5×10⁻¹⁹ J
Frequency of photon = ?
Solution:
Formula;
E = hf
h = planck's constant = 6.63×10⁻³⁴ Js
5×10⁻¹⁹ J = 6.63×10⁻³⁴ Js ×f
f = 5×10⁻¹⁹ J / 6.63×10⁻³⁴ Js
f = 0.75×10¹⁵ s⁻¹
The frequency of photon is 0.75×10¹⁵ s⁻¹.
The transfer of electrons is an ionic bond, therefore, we need to determine which substance includes an ionic bond.
CO2, is a covalent bond, which is the sharing of electrons, not transfer.
KBr, is an ionic bond, because (k) loses an electron to bromine.
So, our final answer is:- <span>(3) KBr</span>
