A 2.200-g sample of quinone (C6H4O2) is burned in a bomb calorimeter whose total heat capacity is 7.854<span> kJ/°C. The temperature of the calorimeter increases from 23.44 to </span>30.57 °C<span>. </span>
What represent ???( the molecules get dissolved in water)..
Answer:
1.94 L
Explanation:
21°C = 21 +273 = 294 K
27°C = 27 + 273 = 300 K
T1/V1 = T2/V2
294 K/1.9 L = 300 K/x L
x = (1.9*300)/294 ≈ 1.94 L
Answer:
% yield = 82.5%
Explanation:
HgO + 2Cl₂ → HgCl₂ + Cl₂O
Our reactants are:
Our products are:
We do not have information about moles of reactants, but we do know the theoretical yield and the grams of product, in this case Cl₂O, we have produced.
Percent yield = (Yield produced / Theoretical yield) . 100
Theoretical yield is the mass of product which is produced by sufficent reactant. We replace data:
% yield = (0.71 g/0.86g) . 100 = 82.5%
Answer:
0 meters
Explanation:
I guessed on the test and I got it right lol.
