I believe it's answer #3. Logically, at least.
You can test #1 through trial and error.
You can experiment #2 also through trial and error.
You cannot test #3 through trial and error, because that would be catastrophic.
You can test #4 through a survey and individual study and data collection.
Answer:
0.0187 M
Explanation:
Step 1: Write the balanced neutralization reaction
NaOH + HCl ⇒ NaCl + H₂O
Step 2: Calculate the reacting moles of HCl
18.7 mL of 0.01500 M HCl react.
0.0187 L × 0.01500 mol/L = 2.81 × 10⁻⁴ mol
Step 3: Calculate the reacting moles of NaOH
The molar ratio of HCl to NaOH is 1:1. The reacting moles of NaOH are 1/1 × 2.81 × 10⁻⁴ mol = 2.81 × 10⁻⁴ mol.
Step 4: Calculate the molarity of NaOH
2.81 × 10⁻⁴ moles are in 15.00 mL of NaOH.
[NaOH] = 2.81 × 10⁻⁴ mol/0.01500 L = 0.0187 M
The chemical reaction that the situation demonstrates would be a double replacement reaction.
In double replacement reactions, the two reactants participating in the reaction are similarly built in terms of their chemical bonds and they exchange ions to form the products of the reaction. Two products are also formed from the two reactants.
It is as opposed to single replacement reactions in which the two reactants are not similar bond-wise. One of the reactants replaces or displaces one of the ions in another reactant.
In this case, the situation can be represented as follows:
Amanda-Janice + Deja-Eden ----> Amanda-Eden + Deja-Janice
Thus, it is a form of double replacement reaction.
More on double replacement reactions can be found here: brainly.com/question/392491?referrer=searchResults
Answer:
Weight of element X = 14.01 gram
Explanation:
Mass percentage is calculated by using :


Mass of O = 16.0 gram
let mass of X = X grams = ?
Mass of XO2 = mass of X + 2(mass of O)
Mass of XO2 = X + 2(16)
Mass of XO2 = X + 32
Total mass of O in the compound = 2(16) = 32 grams
Percent O = 69.55 %









weight of element X = 14.01 gram
14.01 is mass of nitrogen N
The correct formula of this element is NO2
Answer:
Lithium (Li)
Explanation:
Lithium has an atomic number of 3