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Alisiya [41]
1 year ago
6

A 250 ml sample of saturated a g o h solution was titrated with h c l , and the endpoint was reached after 2. 60 ml of 0. 0136 m

h c l was dispensed. Based on this titration, what is the k s p of a g o h ?.
Chemistry
1 answer:
nata0808 [166]1 year ago
5 0

A 250 ml sample of saturated a g o h solution was titrated with h c l , and the endpoint was reached after 2. 60 ml of 0. 0136 m h c l was dispensed. Based on this titration, what is the k s p of a g o h <u>. Ksp=1.9×10⁻⁸</u>

<h3>What is titration?</h3>

Titration is a typical laboratory technique for quantitative chemical analysis used to calculate the concentration of a specified analyte. It is also referred to as titrimetry and volumetric analysis (a substance to be analyzed). A standard solution with a known concentration and volume is prepared as the reagent, also known as the titrant or titrator. To ascertain the concentration of the analyte, the titrant reacts with an analyte solution (also known as the titrand). The titration volume is the amount of titrant that interacted with the analyte.

A typical titration starts with a beaker or Erlenmeyer flask being placed below a calibrated burette or chemical pipetting syringe that contains the titrant and a little amount of the indicator (such as phenolphthalein).

To learn more about titration from the given link:

brainly.com/question/186765

#SPJ4

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The volume of the stock solution that has a concentration of 1.5 M SO2 and is diluted to a 0.54 M solution with a volume of 0.18 L is 0.065L.

<h3>How to calculate volume?</h3>

The concentration of a solution can be calculated using the following formula:

C1V1 = C2V2

Where;

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1.5 × V1 = 0.54 × 0.18

1.5V1 = 0.0972

V1 = 0.0972 ÷ 1.5

V1 = 0.065L

Therefore, the volume of the stock solution that has a concentration of 1.5 M SO2 and is diluted to a 0.54 M solution with a volume of 0.18 L is 0.065L.

Learn more about volume at: brainly.com/question/1578538

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<u><em>Hope this helps and I get brainliest <3</em></u>

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