Question

The value of x varies directly with y, and whenX= 2/3, y = 6. Find the value of y when x = 10-24A.y=9B.y=4C. y=93D.y=1

Answer 1

Problem

Solution

for this case we know that when x =2/3 , y= 6

$10\frac{1}{3}=\frac{10\cdot3+1}{3}=\frac{30+1}{3}=\frac{31}{3}$

Then we want to find the value of y= ? when x= 10 1/3 = 31/3 and we can do this:

6/(2/3) = y/(31/3)

$\frac{6}{\frac{2}{3}}=\frac{y}{\frac{31}{3}}$$y=\frac{31}{3}\cdot\frac{6}{\frac{2}{3}}=\frac{31}{3}\cdot\frac{3}{2}\cdot\frac{6}{1}=\frac{31\cdot3\cdot6}{3\cdot2\cdot1}=93$

And solving for y we got:

y = (3/2) * 6 * (31/3) = 31*3 = 93

C. y= 93