Answer:
Please post a picture with higher quality, I cannot read this one
Step-by-step explanation:
Answer:
Step-by-step explanation:
There are a lot of conversion factors involved in this question.
First of all the radius of Mercury's orbit is 0.4 times that of the earth. The earth's distance from the sun is about 93 million miles. So Mercury's distance or radius is 93 * 0.4 = 37.2 million miles.
The circumference = 2 * pi * r
The circumference = 6.28 * 37200000 = 233616000 miles
This is accomplished in 88 days.
88 days [24 hours/day] * [3600 sec / hour] = 7603200 seconds
88 days = 7603200 second
Rate of travel = miles / second
Rate of travel = 233616000 / 7603200
Rate of travel = 30.726 miles / second
This number was not given so I had to derive it. The official number does not disagree a great deal from this number. It just depends on what constants you use.
1 mile = 1.6 km
30.725 miles = x Cross multiply
x = 1.6 * 30.725
x = 49.16 km/ second
I cannot go any further because you have not provided any givens. The answers do vary quite a bit because I have assumed that Mercury's orbit is a circle. It really is not. It is more like an ellipse.
The official speed in km/sec = 47 which means the answer I have given is very close. A more accurate answer would require that you put the numbers in the blanks that you were given.
The coordinates of the missing endpoints F according to the task content is; (5, 4).
<h3>What are the coordinates of the missing endpoint F in the task content?</h3>
Since the midpoint of the line joining the two points is given as: E; (1, -2).
The coordinates of the endpoint, f can be evaluated as follows;
x-axis;
2(1) = x + (-3); x = 2+3 = 5.
y-axis;
2(-2) = y + (-8) = 4.
The coordinates of f are therefore; (5, 4).
Read more on midpoint of lines;
brainly.com/question/5566419
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Another way to solve this is to use the Midpoint Formula. The midpoint of a segment joining points
and
is
So the midpoint of your segment is
Perhaps it helps to see that the x-coordinate of the midpoint is just the average of the x-coordinates of the points. Ditto for the y-coordinate of the midpoint; just average the y's.
Obtuse triangle if that’s what you’re asking