Answer:
at the atomic level because of the movement of elctrons
The net force acting on the center O is 4.495 X 10⁹ N
<u>Explanation:</u>
Given:
Charge-
q₁ = 4C
q₂ = 3C
q₃ = -5C
q₄ = 2C
q₅ = 1C
Side of the square = 4cm
Net force acting on the center, F = ?
Length of the side of the square is 4cm
The length of the diagonal will be 4√2
The length of half diagonal = 4√2 / 2 = 2√2
Force acting on the center of the square is:
Here, k is coulomb's constant and the value is
k = 8.99 x 10⁹ N m2 / C2
On substituting the value, we get:
Therefore, the net force acting on the center O is 4.495 X 10⁹ N
The magnitude of the average force that the ball exerts against his glove is 600 N
<h3>Further explanation</h3>
Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.
F = Force ( Newton )
m = Object's Mass ( kg )
a = Acceleration ( m )
Let us now tackle the problem !
<u>Given:</u>
mass of ball = m = 0.15 kg
initial speed of ball = u = 40 m/s
final speed of ball = v = 0 m/s
distance = d = 20 cm = 0.2 m
<u>Asked:</u>
average force = F = ?
<u>Solution:</u>
<em>We will use </em><em>Newton's Law of Motion</em><em> to solve this problem as follows:</em>
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Dynamics
Answer:
E = 1.25×10¹³ N/m²
Explanation:
Young's modulus is defined as:
E = stress / strain
E = (F / A) / (dL / L)
E = (F L) / (A dL)
Given:
F = 10 kg × 9.8 m/s² = 98 N
L = 1 m
dL = 10⁻⁵ m
A = π/4 (0.001 m)² = 7.85×10⁻⁷ m²
Solve:
E = (98 N × 1 m) / (7.85×10⁻⁷ m² × 10⁻⁵ m)
E = 1.25×10¹³ N/m²
Round as needed.
A tsp
1 milliliter equals 0.202. US teaspoons. boi did that help