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Blizzard [7]
3 years ago
9

A car travelling at 15m/s comes to a rest in a distance of 14m when the brakes are applied. Calculate the deceleration of the ca

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Marking brainliest :)
Physics
2 answers:
vlada-n [284]3 years ago
6 0

Answer:

force of the breaks is 6650 N, direction opposite to direction of movement

Explanation:

malfutka [58]3 years ago
5 0

Answer :

deceleration of the car is a=8.03\ m/s^2

Explanation:

It is given that,  

Initial speed of the car, u = 15 m/s

Final speed of the car, v = 0 (it comes to rest)

Distance covered by the car, d = 14 m

Let a is the acceleration of the car. We know that the rate of change of velocity of an object is called its acceleration. Mathematically, it can be calculated as :

a=\dfrac{v^2-u^2}{2d}

a=\dfrac{-(15)^2}{2\times 14}

a=-8.03\ m/s^2

So, the deceleration of the car is a=8.03\ m/s^2. Hence, this is the required solution.

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spayn [35]

Option D is correct. The speed at which the earth's surface moves because of the earth's rotation will then be equivalent to -10³ km/hr

Speed is a body is defined as the ratio of the distance with respect to the time taken by the body. Mathematically:

Speed = Distance/Time

GIven the following

Distance = 104km/hr

If it is 6:00 p.m. in New York, it is 7:00 a.m. of the next day of the week in Tokyo, this means that the time difference between New York and Tokyo is 11 hours.

Time = -11 hours

Get the required speed

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Speed = -9.454545

Speed = -10km/hr

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Learn more here: brainly.com/question/2583051

4 0
2 years ago
Read 2 more answers
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ANTONII [103]

Answer:

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Explanation:

Given data

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solution

we know function

T(x, y) = 54 /( 7 + x² + y²)

so derivative it x and y direction i.e

dt/dx = -54× 2x / (7 +x² + y²)²    .........................1

dt/dy = -54× 2y / (7 + x² + y²)²      .........................2

now put the value point (1,3) as x = 1 and y = 3 in equation 1 and 2

dt/dx = -54× 2(1) / (7 +(1)² + (3)²)²  

dt/dx = -0.373702

and

dt/dy =  -54× 2(3) / (7 + (1)² + (3)²)²

dt/dy =  -1.121107

7 0
2 years ago
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nirvana33 [79]
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Orlov [11]
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Verdich [7]

Answer:

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Explanation:

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