I need help on that one 2 someone please help
Answer:
A.) 1.3 seconds
B.) 0.42 m
Explanation:
A.) You are given the angle of projection to be 40 degrees and initial velocity of 20m/s.
At vertical component
U = Usin 40 that is,
U = 20sin40
Using the first equation of motion under gravity
V = U - gt
Let V = 0
0 = UsinØ - gt
gt = UsinØ
t = UsinØ/g
Where U = 20 m/s
Ø = 40 degree
g = 9.8 m/s^2
Substitutes all the parameters into the formula
t = 20sin40/9.8
t = 1.3 seconds
Total time of flight T = 2t
T = 2 × 1.3 = 2.6 s
B.) To calculate the maximum height,
You will use the formula
V^2 = U^2 - 2gH
At maximum height, V = 0
2gH = Usin^2Ø
H = Usin^2Ø/ 2g
Substitutes all the parameters into the formula
H = 20 sin^2(40) ÷ 2(9.8)
H = 8.2635/19.6
H = 0.42 m
Answer:
1.98 x 10⁻⁷ F
Explanation:
w = width of the sheet = 5.9 cm = 0.059 m
L = length of the sheet = 5.6 m
Area of the sheet is given as
A = L w = (5.6) (0.059) = 0.3304 m²
d = distance between the sheets = 3.1 x 10⁻⁵ m
k = dielectric constant of teflon = 2.1
Capacitance is given as
C = 1.98 x 10⁻⁷ F
