Answer
given,
Time period= T = 1.5 s
If it's moving through equilibrium point at t₀= 0 with v = 1.0 m/s
v_max=1.00 m/s
we know,
v_ max=A ω
v = A sin (ωt)
-0.50= -1.00 sin (ωt)
sin (ωt) = 0.5



t = 0.125 s
we have time period T=1.5 it is the time to complete one oscillation
means from eq to right,then left,then eq,then left,then from right to eq
time taken for left = t/4 = 0.125/4 = 0.375 s
smallest value of time
=0.375 + 0.125
= 0.50 sec
Explanation:
<em>Here </em><em>it </em><em>is </em><em>given </em>
<em>Work </em><em>(</em><em>W) </em><em> </em><em>=</em><em> </em><em>3</em><em>5</em><em>6</em><em>0</em><em> </em><em>J</em>
<em>Time </em><em>(</em><em>t) </em><em> </em><em>=</em><em> </em><em>5</em><em>5</em><em> </em><em>sec</em>
<em>power </em><em>(</em><em>P) </em><em> </em><em>=</em><em> </em><em>?</em>
<em>We </em><em>know </em><em>we </em><em>have </em><em>the </em><em>formula </em>
<em>
</em>
<em>P </em><em>=</em><em> </em><em>3</em><em>5</em><em>6</em><em>0</em><em>/</em><em>5</em><em>5</em>
<em>P </em><em>=</em><em> </em><em>6</em><em>4</em><em>.</em><em>7</em><em>3</em><em> </em><em>watt</em>
Answer:
Linear momentum= Mass*Velocity
P=mv
P=60*10
P=600Kg m/s
Answer:
the scattering of short wavelengths as light
passes through the atmosphere
The answer is: " 5 g / cm³ " .
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Explanation:
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Density = mass divided by volume ; or: "D = m / V " ;
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and is expressed as: "mass per unit volume" ;
The mass, "m", is expressed in units of "g" (grams) ; and
the volume, "V" is expressed in units of "cm³ " or "mL" ; ("cm³ ", in this case);
{Note the exact conversion: " 1 cm³ = 1 mL " .} .
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So, if: the mass, "m = 100 g" {given} ;
and the volume, " V = 20 cm³ " {given} ;
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Plug these values into the formula/equation to solve for the density, "D" ;
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D = m / V = (100 g) / (20 cm³)
= (100 ÷ 20) g / cm³ = 5 g /cm³ .
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The answer is: " 5 g / cm³ " .
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