Answer:
speed = distance over time; 1 mile = 1609 meters. 8.9 miles per hour.
Explanation:
:)
Answer:
Rt = 908.25 [ohm]
Explanation:
In order to solve this problem, we must remember that the resistors connected in series are added up arithmetically.
In this case, R2 and R3 are in series therefore.
R₂₃ = 200 + 470
R₂₃ = 670 [ohm]
Now this new resistor (R₂₃) is connected in parallel with the resistor R4. therefore we must use the following arithmetic expression, to add resistances in parallel.
In this way R₁, R₅ and R₄₋₂₃ are connected in series.
Rt = R₁ + R₅ + R₄₋₂₃
Rt = 150 + 270 + 488.25
Rt = 908.25 [ohm]
I think it’s A.) it explains why the universe is made up of matter
Chameleon tongue reaches 23 cm.
Train's final speed is 32 m/s.
The distance the tongue travels is divided into 2 phases.
1. The acceleration phase.
2. The coasting phase.
For the acceleration phase, the formula d = 0.5AT^2 determines how far the tongue travels while accelerating. The during the coasting phase, the tongue continues onward without changing its velocity, so it's formula is d = VT. The peak velocity of the tongue will be reached after 20 ms. So let's calculate it.
d = 0.5AT^2
d = 0.5*290 m/s^2 * (0.020 s)^2
d = 145 m/s^2 * 0.0004 s^2
d = 0.058 m
Now to handle coasting
d = 0.058 m + 0.030 s * 290 m/s^2 * 0.20 s
d = 0.058 m + 0.174 m
d = 0.232 m
Rounding to 2 significant digits gives 0.23 meters, or 23 cm.
For the train, we need to determine the acceleration. We know the velocity changed from 5.0 m/s to 14.0 m/s over a period of 8.0 seconds. So the acceleration is:
(14.0 m/s - 5.0 m/s)/8.0 s = (9.0 m/s)/8.0 s = 1.125 m/s^2
At the edge of town, the train is traveling at 14 m/s and accelerates at 1.125 m/s^2 for 16 seconds, so:
14 m/s + 1.125 m/s^2 * 16 s = 14 m/s + 18 m/s = 32 m/s
So the final speed of the train is 32 m/s