a) Mass of gasiline = 18.9 kg; b) distance travelled = 204 mi
a) <em>Mass of gasoline
</em>
<em>Step 1</em>. Convert <em>$CDN to $US</em>
$US = $30.00 CDN × (0.942$US/$1 CDN) = $28.26 US
<em>Step 2</em>. Calculate the <em>volume of gasoline
</em>
V = $28.26 US × (1 gal gasoline/$3.82 US) = 7.399 gal
<em>Step 3</em>. Convert <em>gallons to litres
</em>
V =7.399 gal × (3.785 L/1 gal) = 28.00 L
<em>Step 4</em>. Calculate the <em>mass of the gasoline
</em>
Mass = 28 000 mL × (0.674 g/1 mL) = 18 900 g = 18.9 kg
<em>
b) Distance travelled
</em>
<em>Step 1</em>. Calculate the <em>kilometres</em>
Kilometres = 28.00 L × (100 km/8.53 L) = 328.3 km
<em>Step 2</em>. Convert <em>kilometres to miles</em>
Miles = 328.3 km × (1 mi/1.609 km) = <em>204 mi</em>
Answer:1.01
Explanation:∆G(system)= ∆G(product) - ∆G(reactant)
Therefore, we have: -32 - 209.2 = -242.09 kj/mol.
Also, ∆G(system)= -RT ln kp ----{*}
R= 8.314, T= 298, kp =? , ∆G(system)= -242.09 kj/mol.
We can now substitute into equation {*}.
I.e, -242.09kj/mol= -8.314×298 ln kp
-242.09= -24477.572 ln kp
In kp= - 242.09÷ -24477.572
ln kp= 0.00989
kp= 1.0099.
~ 1.01
Answer:
Weight of element X = 14.01 gram
Explanation:
Mass percentage is calculated by using :
Mass of O = 16.0 gram
let mass of X = X grams = ?
Mass of XO2 = mass of X + 2(mass of O)
Mass of XO2 = X + 2(16)
Mass of XO2 = X + 32
Total mass of O in the compound = 2(16) = 32 grams
Percent O = 69.55 %
weight of element X = 14.01 gram
14.01 is mass of nitrogen N
The correct formula of this element is NO2
Answer: B
Explanation: The clouds act almost like a lid. Think of it like when you put tin foil over food before it goes in the oven. so that even after it is removed from the heat the tin foil traps it causing it to stay warm.
AIF3
Hope this helps, God bless and have a good day.