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2 years ago

Can anything change solutions? Be specific!

Chemistry

2 answers:

Julli [10]2 years ago

8 0

What solutions are u referring to

trasher [3.6K]2 years ago

4 0

What kind of solutions?

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The movement of genes from one population to another is called _____.

a_sh-v [17]

Answer:gene flow

Explanation:Its right

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3 years ago

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Sugar is easily soluble in water and has a molar mass of 342.30 g/mol. What is the molar concentration of a 259.8 mL aqueous sol

DanielleElmas [232]

Answer:

$M=0.822M$

Explanation:

Hello,

In this case, given the mathematical definition of molar concentration as the moles of solute divided by the liters of solution:

$M=\frac{n}{V}$

We can easily compute it by firstly computing the moles of sugar by using its molar mass:

$n=73.1g*\frac{1mol}{342.30g} =0.214mol$

After that, we compute the concentration by realizing 259.8 mL equals 0.2598 L:

$M=\frac{0.214mol}{0.2598L}\\ \\M=0.822mol/L$

Or just:

$M=0.822M$

Considering molar units as mol/L

Best regards.

5 0

3 years ago

If an atom has 22 protons 28 neutrons 20 electrons what would its atomic number be

AURORKA [14]

Answer:

Explanation:

The atomic number indicates the amount of protons, so it would be 22

4 0

2 years ago

You decided to prepare a phosphate buffer from solid sodium dihydrogen phosphate (NaH2PO4) and disodium hydrogen phosphate (Na2H

KIM [24]

Answer:

For disodium hydrogen phosphate:

5.32g Na2HPO4

For sodium dihydrogen phosphate:

7.65g Na2HPO4

Explanation:

First, you have to put all the data from the problem that you going to use:

-NaH2PO4 (weak acid)

-Na2HPO4 (a weak base)

-Volume = 1L

-Buffer pH = 7.00

-Concentration of [NaH2PO4 + Na2HPO4] = 0.100 M

What we need to find the pKa of the weak acid, in this case NaH2PO4, for that you need to find the Ka (acid constant) of NaH2PO4, and for this we use the pKa of the phosphoric acid as follow:

H3PO4 = H2PO4 + H+ pKa1 = 2.14

H2PO4 = HPO4 + H+ pKa2 = 6.86

HPO4 = PO4 + H+ pKa3 = 12.4

So, for the preparation of buffer, you need to use the pKa that is near to the value of the pH that you want, so the choice will be:

pKa2= 6.86

Now we going to use the Henderson Hasselbalch equation for the pH of a buffer solution:

pH = pKa2 + log [(NaH2PO4)/(Na2HPO4)]

The solution of the problem is attached to this answer.

Download odt

7 0

3 years ago

If the force is 2,500 N and the acceleration is 500 m/s/s, what is the objects mass

ra1l [238]

The mass is 5kg
I hope this helps

5 0

2 years ago