a)Fc = 481741.9706 N is the magnitude of the force on the bolt from the axle. b)If not, the computation will stay the same because the blade's uniform mass and angular velocity.
<h3>How would you define magnitude?</h3>
In the physics perspective, magnitude is just "distance or quantity." It displays an object's size, direction, or speed, whether relative or absolute. It is used to indicate that something has a certain size or scope. In physics, magnitude often refers to a size or amount.
<h3>Briefing:</h3>
The mass of the blade is m.
The blade's linear speed is expressed as v.
The blade's angular velocity is ω
L is the length of the blade.
Length of the helicopter rotor blade is, L=7.8 m
Mass of the helicopter rotor blade, m=110 kg
When the rotor is revolving at 320 revs per minute, the amount of centripetal force acting on the bolt from the axle is
Fc = mv²/r = mω²L/2
Fc = 110 * (320 * 2π/60)² * 7.8/2
Fc = 481741.9706 N.
The blade can be thought of as a point mass at its centre of mass, according to the equation above. If not, the computation will stay the same because the blade's uniform mass and angular velocity.
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The complete question is -
A uniform helicopter rotor blade is 7.80 m long, has a mass of 110 kg, and is attached to the rotor axle by a single bolt. (a) What is the magnitude of the force on the bolt from the axle when the rotor is turning at 320 rev/min? (Hint:For this calculation the blade can be considered to be a point mass at its center of mass. Why?) (b) Calculate the torque that must be applied to the rotor to bring it to full speed from rest ?
