a)Fc = 481741.9706 N is the magnitude of the force on the bolt from the axle. b)If not, the computation will stay the same because the blade's uniform mass and angular velocity.
<h3>How would you define magnitude?</h3>
In the physics perspective, magnitude is just "distance or quantity." It displays an object's size, direction, or speed, whether relative or absolute. It is used to indicate that something has a certain size or scope. In physics, magnitude often refers to a size or amount.
<h3>Briefing:</h3>
The mass of the blade is m.
The blade's linear speed is expressed as v.
The blade's angular velocity is ω
L is the length of the blade.
Length of the helicopter rotor blade is, L=7.8 m
Mass of the helicopter rotor blade, m=110 kg
When the rotor is revolving at 320 revs per minute, the amount of centripetal force acting on the bolt from the axle is
Fc = mv²/r = mω²L/2
Fc = 110 * (320 * 2π/60)² * 7.8/2
Fc = 481741.9706 N.
The blade can be thought of as a point mass at its centre of mass, according to the equation above. If not, the computation will stay the same because the blade's uniform mass and angular velocity.
To know more about Magnitude visit:
brainly.com/question/1313542
#SPJ4
The complete question is -
A uniform helicopter rotor blade is 7.80 m long, has a mass of 110 kg, and is attached to the rotor axle by a single bolt. (a) What is the magnitude of the force on the bolt from the axle when the rotor is turning at 320 rev/min? (Hint:For this calculation the blade can be considered to be a point mass at its center of mass. Why?) (b) Calculate the torque that must be applied to the rotor to bring it to full speed from rest ?