A. making the surface rougher
A = mg∆h = 10•10•1 = 100J
The pressure dropped by 24 MB in the storm's center from November 9, 1200z, until November 11, 0000z.
Using the attached map below, in the morning of November 9, the pressure situated at the storm's center = 1000 MB isobar located at the center.
Meanwhile, on November 11, 0000z the pressure situated at the storm's center = 976 MB isobar
The difference in this pressure is regarded as the pressure drop in the storm's center and it is determined as follows;
= 1000 MB - 976 MB
= 24 MB
Therefore, we can conclude that the pressure drop by 24 MB in the storm's center from November 9, 1200z, until November 11, 0000z.
Learn more about pressure drop in an isobaric process here:
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That depends on my mass and the height of the ladder.
Answer:
7.24 ohm
Explanation:
Let R1 and R2 are resistance of two resistors.
Emf=E=20 V
Current,I=2 A
Current,I'=10 A
We have to find the magnitude of the greater of the two resistances.
In series


By using the formula

...(1)
In parallel







Substitute the value




By using quadratic formula




Substitute the value


Hence, the magnitude of the greater of the two resistance=7.24 ohm