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Sholpan [36]
3 years ago
12

Define infer in science.

Physics
1 answer:
tia_tia [17]3 years ago
8 0

Answer :Scientific Definition of Inference

In science, there are a few different types of inferences, but in general an inference is: “An educated guess made through observation.” You might use these inferences to share a potential reason why something happens or how it happens.

Explanation:

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You can increase friction by
tia_tia [17]
A. making the surface rougher
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3 years ago
The work done to lift a 10kg object to a height of 1m above the ground is
vlada-n [284]
A = mg∆h = 10•10•1 = 100J
8 0
3 years ago
How much did the pressure drop in the storm's center from November 9, 1200z, until November 11, 0000z
o-na [289]

The pressure dropped by 24 MB in the storm's center from November 9, 1200z, until November 11, 0000z.

Using the attached map below, in the morning of November 9, the pressure situated at the storm's center = 1000 MB isobar located at the center.

Meanwhile, on November 11, 0000z the pressure situated at the storm's center = 976 MB isobar  

The difference in this pressure is regarded as the pressure drop in the storm's center and it is determined as follows;

= 1000 MB - 976 MB

= 24 MB

Therefore, we can conclude that the pressure drop by 24 MB in the storm's center from November 9, 1200z, until November 11, 0000z.

Learn more about pressure drop in an isobaric process here:

brainly.com/question/13089696?referrer=searchResults

3 0
2 years ago
If it took 10sec to climb the ladder what was your power in watts nd kilowatt?
Vaselesa [24]
That depends on my mass and the height of the ladder.
4 0
3 years ago
When a 20-V emf is placed across two resistors in series, a current of 2.0 A is present in each of the resistors. When the same
ehidna [41]

Answer:

7.24 ohm

Explanation:

Let R1 and R2 are resistance of two resistors.

Emf=E=20 V

Current,I=2 A

Current,I'=10 A

We have to find the magnitude of the greater of the two resistances.

In series

R=R_1+R_2

V=IR

By using the formula

20=2(R_1+R_2)

R_1+R_2=\frac{20}{2}=10...(1)

In parallel

\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}

\frac{1}{R}=\frac{R_2+R_1}{R_1R_2}

R=\frac{R_1R_2}{R_1+R_2}

20=10(\frac{R_1R_2}{R_1+R_2}

2=\frac{R_1R_2}{10}

R_1R_2=20

R_2=\frac{20}{R_1}

Substitute the value

\frac{20}{R_1}+R_1=10

R^2_1+20=10R_1

R^2_1-10R_1+20=0

R_1=\frac{10\pm\sqrt{(-10)^2-4(20)}}{2}

By using quadratic formula

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

R_1=\frac{10\pm 2\sqrt 5}{2}

R_1=\frac{10+2\sqrt 5}{2}=5+\sqrt 5=7.24 ohm

R_1=\frac{10-2\sqrt 5}{2}=2.76 ohm

Substitute the value

R_2=\frac{20}{7.24}=2.76 ohm

R_2=\frac{20}{2.76}=7.24 ohm

Hence, the magnitude of the greater of the two resistance=7.24 ohm

8 0
3 years ago
Read 2 more answers
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