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iren [92.7K]
11 months ago
15

Complete the order pairs below so they satisfy the equation Y=-3x+2Complete the order pairs (0,__) (7,__) (__,17)

Mathematics
1 answer:
Alchen [17]11 months ago
8 0

The ordered pairs which satisfy the equation are  (0,2) , (7,19) (-5,17) .

Finding the values of the variables that result in equality is the first step in solving a variable equation.

  • The values of the unknown variables that fulfil the equality are the equation's solutions, also known as the variables for which the equation must be solved.
  • The two forms of equations are identity equations and conditional equations.
  • All feasible values of the variables share the same identity. Only specific instances where the values of the variables coincide can result in the truth of a conditional equation.
  • Two phrases are combined into one by using the equals sign ("="). The "left hand side" and "right hand side" of the equation refer to the expressions on each side of the equals sign. It's typical.

At x = 0 the value of y from the equation is :

y = 2

At x = 7 , y =-19

at y=17 , x= -5

Therefore the ordered pairs are :(0,2) , (7,19) (-5,17) .

To learn more about equation visit:

brainly.com/question/10413253

#SPJ1

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Answer:

x=34

Step-by-step explanation:

132-64=

68/2=

34

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7 0
2 years ago
If 3 to the power of x+1 = 81 and 81 to the power of x-y = 3 then what is the value of x and y?
fgiga [73]
From 1st condition:

3^(x+1)=81
Take log on both sides,
➡ log [3^(x+1)]=log81
Use the property: log(x^a)=a logx
➡ (x+1) log 3=log(3⁴)
➡ (x+1) log 3=4×log 3
➡ (x+1)=4 (log 3 /log 3)
➡ x+1=4
➡ x=3➡↪➡↪ ANS

From 2nd condition, (Same process are repeated)

81^(x-y)=3
➡ 3^4(x-y)=3
➡ log [3^4(3-y)]=log 3
➡ 4(3-y) log 3=log 3
➡ (3-y)=(log 3)/(4log 3)
➡ 3-y=(1/4)
➡ y=11/4 ➡↪➡↪ ANS
4 0
3 years ago
If U = {x: X € N, 1 &lt; × &lt; 15)
Inessa05 [86]

Answer:

Step-by-step explanation:

Given:

U = {x: X € N, 1 < × < 15) = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15}

A = {2,4,6,8,10,12,14}

B = {3,6,9,12,15}

C = {5,10,15}

(a) Verify A(BnB)=(AUB)(AUB)

A U (B n B)

=  {2,4,6,8,10,12,14} U (  {3,6,9,12,15} n  {3,6,9,12,15} )

=  {2,4,6,8,10,12,14} U {3,6,9,12,15}

=  {2,3,4,6,8,9,10,12,14,15}

( A U B) n (A U B)

= {2,3,4,6,8,9,10,12,14,15} n {2,3,4,6,8,9,10,12,14,15}

= {2,3,4,6,8,9,10,12,14,15}

Therefore

A U (B n B)  =  ( A U B) n (A U B)

verifies

(b) Verify An(BUC)=(AnB)u(AnC)

A n ( B U C)

=  {2,4,6,8,10,12,14} n ( {3,6,9,12,15} U {5,10,15} )

=  {2,4,6,8,10,12,14} n {3,5,6,9,10,12,15}

= {6,10,12}

( A n B ) U ( A n C )

= ( {2,4,6,8,10,12,14} n {3,6,9,12,15} ) U ( {2,4,6,8,10,12,14} n {5,10,15} )

= {6,12} U {10}

= {6,10,12}

Therefore

A n ( B U C) = ( A n B ) U ( A n C )

verifies

(c) Verify AU(BUC)=(AUB)U(AUC)​

AU(BUC)

=  {2,4,6,8,10,12,14}U{3,6,9,12,15}U{5,10,15}

= {2,3,4,5,6,8,9,10,12,14,15}

(AUB)U(AUC)​

=  ({2,4,6,8,10,12,14}{3,6,9,12,15})U({2,4,6,8,10,12,14}U{5,10,15})

= {2,3,4,6,8,9,10,12,14,15}U{2,4,5,6,8,10,12,14,15}

= {2,3,4,5,6,8,9,10,12,14,15}

Therefore

AU(BUC)=(AUB)U(AUC)​

verifies

5 0
3 years ago
2-31. Write an equation and solve it to find the answer to the question below.  Use the 5-D Process to help you write the equati
raketka [301]

r = 25+b

n = 3b

n+r+b=435

3b+25+b+b=435

5b+25=435

5b=210

b=42

r = 25+42 = 67

n = 3(42) = 126

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=-5%283.15-%5Cfrac%7B21%7D%7B20%7D%20%29%2B7" id="TexFormula1" title="-5(3.15-\frac{21}{20} )+7
Maksim231197 [3]
The answer is -7/2 or -3.5
8 0
3 years ago
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