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labwork [276]
1 year ago
7

7 1 point

Chemistry
1 answer:
kolezko [41]1 year ago
3 0

1. The volume occupied by 8.8 g of H₂O vapor is 11.0 L

2. The mass of the oxygen (O₂) in the cylinder is 9.28 grams

1. How to determine the volume

  • Mass of H₂O = 8.8 g
  • Molar mass of H₂O = 18 g/mol
  • Mole of H₂O = 8.8 / 18 = 0.49 mole
  • Volume of H₂O =?

The volume occuppied by the water, H₂O vapour can be obtained as follow:

1 mole of H₂O = 22.4 L

Therefore,

0.49 mole of H₂O = (0.49 mole × 22.4 L) / 1 mole

0.49 mole of H₂O = 11.0 L

Thus, the volume of H₂O is 11.0 L

2. How to determine the mass

We know that:

22.4 L = 1 mole of O₂

Therefore,

6.5 L = (6.5 L × 1 mole) / 22.4 L

6.5 L = 0.29 mole of O₂

Thus, we can obtain the mass as follow:

  • Molar mass of O₂ = 32 g/mole
  • Mole of O₂ = 0.29 mole
  • Mass of O₂ =?

Mass = mole × molar mass

Mass of O₂ = 0.29 × 32

Mass of O₂ = 9.28 grams

Learn more about volume and mole:

brainly.com/question/22311771

brainly.com/question/13314627

#SPJ4

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Express the diameter of a ground-state hydrogen atom in meters using a power of 10.
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<span>Throughout the development of particle physics, scientists have created different models to understand the atom. When we are talking about the diameter of an atom, we would refer to the Bohr radius, which is the radius from the nucleus to the orbiting electron. In this case, a hydrogen atom has one electron, and the Bohr radius in the ground state is 5.29 x 10^{-11} meters. To find the diameter, we just multiply the Bohr radius by 2. diameter = 2 x 5.29 x 10^{-11} meters diameter = 10.58 x 10^{-11} meters diameter = 1.058 x 10^{-10} meters The diameter of a hydrogen atom in ground state is: 1.058 x 10^{-10} meters</span>
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The higher the pH, the less acidic the solution
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<em>yh thats true lol, ty for that very interesting fact</em>

6 0
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Q3 - Complete the word equation *
tia_tia [17]
Whoever gave u this homework, doesnt really understand the concept
5 0
3 years ago
Need help !!!!! ASAP
Oksi-84 [34.3K]
<h2>Hello!</h2>

The answer is:

The approximate volume is 9.84 L.

V=9.84L

<h2>Why?</h2>

Since we are given the numer of moles, the temperature and the pressure of the gas, we can calculate the approximate volume using The Ideal Gas Law.

The Ideal Gas Law is based on Boyle's Law, Gay-Lussac's Law, Charles's Law, and Avogadro's Law, and it's described by the following equation:

PV=nRT

Where,

P is the pressure of the gas.

V is the volume of the gas.

n is the number of moles of the gas.

T is the absolute temperature of the gas (Kelvin).

R is the ideal gas constant, which is equal to:

R=0.082\frac{atm.L}{mol.K}

So, we are given the information:

n=1.5mol\\Temperature=300K\\Pressure=3.75atm

Now, substituting the given information and isolating the Volume from The Ideal Gas Law equation, we have:

PV=nRT

V=\frac{nRT}{P}

3.75atm*V=1.5mol*0.082*\frac{atm.L}{mol.K}*300K

V=\frac{ 1.5mol*0.082*\frac{atm.L}{mol.K}*300K}{3.75atm}\\\\V=\frac{36.9atm.L}{3.75atm}=9.84L

So, the approximate volume is 9.84 L.

V=9.84L

Have a nice day!

7 0
4 years ago
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