After the addition of 6.47 mL of 0.303 M HCl. Solution :- lets first calculate the moles of the NaOCl and HCl Moles = molarity *volume in liter Moles of NaOCl = 0.100 mol per L * 0.053 L =0.0053 mol Moles of HCl =0.303 mol per L *0.00647L=0.00196
Answer:
See explanation
Explanation:
The oxides or hydrides are formed by exchange of valency between the two atoms involved. The group of the atom bonded to oxygen or hydrogen in the binary compound can be deduced by considering the subscript attached to the oxygen or hydrogen atom.
Now let us take the journey;
R2O3- refers to an oxide of a group 13 element, eg Al2O3
R2O - refers to an oxide of group a group 1 element e.gNa2O
RO2 - refers to an oxide of a group 14, 15 or 16 element such as CO2, NO2 or SO2
RH2 - refers to the hydride of a group 12 element Eg CaH2
R2O7 - refers to an oxide of a group 17 element E.g Cl2O7
RH3- refers to a hydride of a group 13 element E.g AlH3
Answer:
Your question was explained in my chemistry book so I just shared the picture
Hope that helps
