What types of elements- metals,

Chemistry

1 answer:

crimeas [40]3 years ago

7 0

Answer:

Noble gases

Explanation:

The noble gases are non-metals that requires the highest amount of energy to remove an electron from their shells.

The reason for this difficult is that their electronic configuration confers a stable configuration them.

The ionization energy is the energy required to remove the most loosely held electrons in an atom.
Due to the special stability of noble gases, it is very difficult to remove electrons from an atom of noble gases.

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Elements riddle: Without my next door neighbor, I wouldn’t be worth 6 cents. Who am I?

zalisa [80]

If I understand this right, the two elements are Nickel and Copper, elements 28 and 28, respectively. A nickel is worth 5 cents, and a penny, originally comprised of copper, is worth one - the total being six cents.

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3 years ago

Hey!!! Chemistry Question about MOLES... Please help...

yulyashka [42]

Answer:

= 13.0 moles O2

Explanation:

1] Given the equation: 2C8H18 + 25 O2 ----> 16CO2 + 18H2O

a. How many moles of oxygen gas are required to make 8.33 moles of carbon dioxide?

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= 13.0 moles O2

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2 years ago

Read 2 more answers

A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f

a_sh-v [17]

Answer:

$m_{H_2O}=39.0g$

Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

$\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})$

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

$m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g$