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abruzzese [7]
1 year ago
10

A chemistry teacher is preparing for a lab that requires each student to have 5 test tubes. If there are 28 students per class,

how many test tubes are required for 6 chemistry classes?
Chemistry
1 answer:
tamaranim1 [39]1 year ago
4 0

840 test tubes will be required in total for all the students for the 6 chemistry classes.

This is a word problem, so we need to deduce the facts;

Each student = 5 test tubes

So, 28 students will need  5 x 28 test tubes = 140 test tubes

140 test tubes are needed for the 28 students for a single chemistry class.

Therefore, for 6 chemistry classes;

Total test tubes = 140 x 6

Total test tubes = 840

For the 6 chemistry classes, a total of 840 test tubes will be needed.

Read more on word problem: brainly.com/question/29797698

#SPJ1

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Which can occur in a physical change?<br> The mass can increase
solong [7]
In a physical change the form changes or the state of the matter. For instance water can freeze and water can melt, but it is still water.

Please vote my answer brainliest! Thanks.
3 0
4 years ago
If I want to say HCl(g), do I need to say the gas form of hydrogen chloride or hydrochloric acid?​
Sergeu [11.5K]

Answer:

  • <u><em>The gas form of hydrogen chloride.</em></u>

Explanation:

Pure hydrogen chloride is a gas. it is formed when hydrogen gas combines with chlorine gas. Tat is indicated by using HCl (g), as you have correctly done in your question. So, strictly speaking HCl is the gas form of hydrogen chloride, and you should not say the gas form of hydrochloric acid.

Hydrogen chloride (the gas) may be dissolved in water, and then it forms aqueous hydrogen chloride, which is indicated as HCl (aq). The solution of hydrogen chloride may also be named hydrochloric acid. So, the name hydrochloric acid should only be used for the aqueous solutions of the acid.

4 0
3 years ago
Answer the following question: In a space shuttle, the CO2 that the crew exhales is removed from the air by a reaction within ca
Ulleksa [173]

Answer:

See Explanation

Explanation:

The unbalanced reaction equation is;

CO2(g) + LiOH(aq) + Li2CO3(aq) + H2O(l)

The balanced chemical reaction equation;

CO2(g) + 2LiOH(aq) + Li2CO3(aq) + H2O(l)

The molar mass of each compound is the sum of the relative atomic masses of the atoms of the elements that compose the compounds.

For CO2

12 + 16(2) = 12 + 32 = 44 g/mol

For LiOH

7 + 16 + 1 = 24 g/mol

For Li2CO3

2(7) + 12 + 3(16) = 74 g/mol

For H2O

2(1) + 16 = 18 g/mol

From the balanced chemical reaction equation, the mole ratio is 1:2:1:1. This is obtained from the stoichiometric coefficient of each reactant in the balanced chemical reaction equation.

From the question;

1 mole of CO2 occupies 22.4 L

x moles of CO2 occupies 825 L

x = 1 mole * 825 L/22.4 L

x = 36.8 moles

From the reaction equation;

1 mole of CO2 produces 1 mole of water

36.8 moles of CO2 produces 36.8 moles of water

Mass of 36.8 moles of water = 36.8 moles * 18 g/mol

= 662 g of water

The answer must have three significant figures because that is the same number of significant figures to which values were given in the question.

6 0
3 years ago
Calculate the number of molecules present in 11 moles of H2O.
DedPeter [7]

Answer:

11 \times 6.022 \times  {10}^{23}  \\  = 66.242\times  {10}^{23} \: of \:  \\ water \: molecules

6 0
3 years ago
A 825 g iron block is heated to 352 degrees C and is placed in an insulated container (of negligible heat capacity) containing 4
Stella [2.4K]

Answer : The final equilibrium temperature of the water and iron is, 537.12 K

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron =  560 J/(kg.K)

c_1 = specific heat of water = 4186 J/(kg.K)

m_1 = mass of iron = 825 g

m_2 = mass of water = 40 g

T_f = final temperature of water and iron = ?

T_1 = initial temperature of iron = 352^oC=273+352=625K

T_2 = initial temperature of water = 20^oC=273+20=293K

Now put all the given values in the above formula, we get:

(825\times 10^{-3}kg)\times 560J/(kg.K)\times (T_f-625K)=-(40\times 10^{-3}kg)\times 4186J/(kg.K)\times (T_f-293K)

T_f=537.12K

Therefore, the final equilibrium temperature of the water and iron is, 537.12 K

8 0
3 years ago
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