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Stels [109]
3 years ago
6

When a reversible reaction is at equilibrium, the concentration of products and the concentration of reactants must be

Chemistry
1 answer:
ivolga24 [154]3 years ago
7 0

Answer:

Constant

Explanation:

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45.6 mL of 0.0600 M Ba(OH)2 is added to 25.0 mL of HCl of unknown concentration. What is the concentration of HCl?
Alex Ar [27]

45.6 mL of 0.0600 M of Ba(OH)_{2} is added to 25.0 mL of HCl of unknown concentration then , the  concentration of HCl is 0.032 M .

Calculation ,

Formula used : M_{1} V_{1} =  M_{2} V_{2}                 ...( 1 )

Where  M_{1}= concentration of Ba(OH)_{2}  =  0.0600 M ( given )

M_{2} = concentration of HCl = ? ( to be find )

 V_{1}= volume of Ba(OH)_{2}  = 25.0 mL  ( given )

V_{2} = volume of HCl = 45.6 mL  ( given )

Now , put the value of all volume and concentration in equation ( 1 ) we get .

0.0600 M ×  25.0 mL =  M_{2}  × 45.6 mL

M_{2}  =  0.0600 M ×  25.0 mL / 45.6 mL = 0.032 M

Therefore , concentration of  unknown concentration of HCl is 0.032 M .

to learn about concentration here ,

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7 0
1 year ago
How does the design of an experiment relate to the method of difference?
BartSMP [9]

Answer:

The design of experiments (DOE, DOX, or experimental design) is the design of any task that aims to describe and explain the variation of information under conditions that are hypothesized to reflect the variation. The term is generally associated with experiments in which the design introduces conditions that directly affect the variation, but may also refer to the design of quasi-experiments, in which natural conditions that influence the variation are selected for observation.

Explanation:

5 0
3 years ago
The water table is the
timofeeve [1]
Here is some different  pics of a water table. I hope this is what you are looking for :). You can click the pictures to in large them. 

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The 1h nmr spectrum of a compound which has the molecular formula c8h8 is shown below. Identify the compound.
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solution:

That is a one benzene ring.

The really messy multiplet at 7.27ppm pretty much can be interpreted as a monosubstituted ring.

After the ring is accounted for, all that's left is C₂H₃. There's one more double bond equivalent, and only two carbons left, so the only possibility is an alkene.

the alkene protons are the signals at 6.7ppm, 5.6ppm, and 5.2ppm. A benzene ring attached to an alkene will shift the proton geminal to it up about 1.3ppm from the normal 5.25ppm, the cis proton up about 0.36ppm, and have not much effect on the proton trans to it.


5 0
4 years ago
Choose all the properties of METALS that make them different from non-metals :
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Answer:

metals-

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