Question

What is the value of Keq for the reaction expressed in scientific notation? 1.6 ´ 10–5 6.2 ´ 10–4 6.2 ´ 104 1.6 ´ 105

Answer 1

The question is incomplete, the complete question is:

Consider the reaction:

$2NOCl\rightleftharpoons 2NO+Cl_2$

At equilibrium, the concentrations are as follows. [NOCl] = 1.4 × 10–2 M [NO] = 1.2 × 10–3 M [Cl2] = 2.2 × 10–3 M What is the value of Keq for the reaction expressed in scientific notation?

A) 1.6 × 10–5

B) 6.2 × 10–4

C) 6.2 × 10+4

D) 1.6 × 10+5

Answer: The correct option is A) $1.6\times 10^{-5}$

Explanation:

The equilibrium constant is defined as the ratio of the concentration of products to the concentration of reactants raised to the power of the stoichiometric coefficient of each. It is represented by the term $K_{eq}$

For the given chemical equation:

$2NOCl\rightleftharpoons 2NO+Cl_2$

The expression for equilibrium constant will be:

$K_{eq}=\frac{[NO]^2}{[Cl_2][NOCl]^2}$

Given values:

$[NO]=1.2\times 10^{-3}M$

$[Cl_2]=2.2\times 10^{-3}M$

$[NOCl]=1.4\times 10^{-2}M$

Putting values in above expression, we get:

$K_{eq}=\frac{(1.2\times 10^{-3})^2\times (2.2\times 10^{-3})}{(1.4\times 10^{-2})^2}\\\\K_{eq}=1.6\times 10^{-5}$

Hence, the correct option is A) $1.6\times 10^{-5}$